The number of grams of gold you can purchase for $15 if Gold cost $8.00 per ounce is 53.26g
Dimensional analysis is a means of representing values using units.
From the question, we are told that Gold cost $8.00 per ounce, this means that:
$8.00 = 1 ounce
In order to calculate the amount in grams you can purchase for $15, we need to know the price in ounces first.
$15.00 = x
Divide both expressions

Next is to convert the ounces to pounds.
1 pound = 16 ounces
y = 1.875 ounces
y = 1.875/16
y = 0.1171875 pounds
Conver 0.1171875 pounds to kg
Since 1kg = 2.2 pounds
z = 0.1171875 pounds
2.2z = 0.1171875
z = 0.1171875/2.2
z = 0.053267kg
Finally, convert 0.053267kg to grams using the conversion rate
1kg = 1000g
0.053267kg = y
y = 0.05326 * 1000
y = 53.26g
This shows that the amount of grams you can purchase for $15 is 53.26g
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Answer:

Explanation:
ΣF=ma
The two forces at play are the force applied and the force due to friction. As they are opposing forces set the direction being pushed as the positive in the x direction. the equation you come out with is 60 - 15=(15)A (we know mass to be 15kg). Solve for 3 m/s^2.
Answer:
(a) g = 8.82158145
.
(b) 7699.990192m/s.
(c)5484.3301s = 1.5234 hours.(extremely fast).
Explanation:
(a) Strength of gravitational field 'g' by definition is
, here G is Gravitational Constant, and r is distance from center of earth, all the values will remain same except r which will be radius of earth + altitude at which ISS is in orbit.
r = 6721,000 meters, putting this value in above equation gives g = 8.82158145
.
(b) We have to essentially calculate centripetal acceleration that equals new 'g'.
here g is known, r is known and v is unknown.
plugging in r and g in above and solving for unknown gives V = 7699.990192m/s.
(c) S = vT, here T is time period or time required to complete one full revolution.
S = earth's circumfrence , V is calculated in (B) T is unknown.
solving for unknown gives T = 5484.3301s = 1.5234hours.
Answer:
F = 8840.7 N
Explanation:
The parameters given are:
Length L = 3 metres
Extension e = 3 × 3 = 9m
Force constant K = 982.3 Newton per metre
From Hook's law,
Provided the elastic limit is not extended, the extension is directly proportional to the force applied.
That is,
F = Ke
Substitute all the parameters into the formula
F = 982.3 × 9
F = 8840.7 N