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Rudik [331]
3 years ago
11

Which era is where dinosaurs came

Physics
2 answers:
vodka [1.7K]3 years ago
7 0
The era that dinosaurs came was in the Mesozoic Era!
AleksAgata [21]3 years ago
5 0
On every continent that represents rocks anything jurrasic on the earths surface
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A body at rest will remain at rest unless acted on by a(an) _____.
andrew11 [14]
The answer is A. external, unbalanced force.
4 0
3 years ago
8. A 12kg bowling ball has a velocity of 8 m/s, and is brought to
Natali5045456 [20]

Answer:

The change in momentum experienced by the bowling ball is 96 kgm/s.

Explanation:

Given;

mass of the bowling ball, m = 12 kg

velocity of the bowling ball, v = 8 m/s

time  of motion, t = 10 s

The change in momentum experienced by the bowling ball is equal to the impulse experienced by the bowling ball.

ΔP = J = F x t

J = ft =\frac{mv}{t} \times t = mv\\\\J = 12 \times 8\\\\J = 96 \ kg.m/s

Therefore, the change in momentum experienced by the bowling ball is 96 kgm/s.

8 0
3 years ago
A circuit with which components has a current with the greatest voltage?
Ymorist [56]
The components in a circuit don't determine the voltages in it.
The voltages are all determined by the battery or power supply
that energizes the circuit.
7 0
3 years ago
Read 2 more answers
A −3.0 nC charge is on the x-axis at x=−9 cm and a +4.0 nC charge is on the x-axis at x=16 cm. At what point or points on the y-
alexdok [17]

Answer:

y = 10.2 m

Explanation:

It is given that,

Charge, q_1=-3\ nC

It is placed at a distance of 9 cm at x axis

Charge, q_2=+4\ nC

It is placed at a distance of 16 cm at x axis

We need to find the point on the y-axis where the electric potential zero. The net potential on y-axis is equal to 0. So,

\dfrac{kq_1}{r_1}+\dfrac{kq_2}{r_2}=0

Here,

r_1=\sqrt{y^2+9^2} \\\\r_2=\sqrt{y^2+15^2}

So,

\dfrac{kq_1}{r_1}=-\dfrac{kq_2}{r_2}\\\\\dfrac{q_1}{r_1}=-\dfrac{q_2}{r_2}\\\\\dfrac{-3\ nC}{\sqrt{y^2+81} }=-\dfrac{4\ nC}{\sqrt{y^2+225} }\\\\3\times \sqrt{y^2+225}=4\times \sqrt{y^2+81}

Squaring both sides,

3\times \sqrt{y^2+225}=4\times \sqrt{y^2+81}\\\\9(y^2+225)=16\times (y^2+81)\\\\9y^2+2025=16y^2-+1296\\\\2025-1296=7y^2\\\\7y^2=729\\\\y=10.2\ m

So, at a distance of 10.2 m on the y axis the electric potential equals 0.

8 0
3 years ago
You push a table 8 meters for 16 minuutes and do 6720 j of work how much power do ypu use
Yuri [45]
P=W/t

P=Power
W=Work
t=Time

Convert 16 minutes in seconds:
16 mins = 960 secs

P=6720/960=7.23 W [Watt]
3 0
3 years ago
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