Answer: In polar covalent bonds a pair of electrons are unequally shared between two atoms, while in nonpolar covalent bonds two atoms share a pair of electrons with each other.
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Explanation:
The initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C
<h3>How to calculate temperature?</h3>
The initial temperature of the copper metal can be calculated using the following formula on calorimetry:
Q = mc∆T
mc∆T (water) = - mc∆T (metal)
Where;
- m = mass
- c = specific heat capacity
- ∆T = change in temperature
According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:
400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)
30,096 = 93.6T - 2246.4
93.6T = 32342.4
T = 345.5°C
Therefore, the initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C.
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Answer:
True
Explanation:
This are acts or actions that concur with situational expectations.
Answer is: more H⁺ ions than OH⁻ ions.
<span>An Arrhenius acid is a
substance that dissociates in water to form hydrogen ions or
protons.
For example, hydrochloric acid dissociate in aqueous
solution to form hydrogen ions (H</span>⁺)
and chloride anion (Cl⁻):<span>
HCl(aq) → H</span>⁺(aq) + Cl⁻<span>(aq).
</span>
An Arrhenius base is a
substance that dissociates in water to form hydroxide ions (OH⁻<span>).
For example lithium hydroxide is an Arrhenius base:</span>
LiOH(aq) → Li⁺(aq) + OH⁻(aq).
The subscript for H in the empirical formula for this compound is 3.
There are 3 steps involved in the construction of empirical formula.
Calculation of empirical formula is as under as ...
Step 1: Divide the % of each atoms which their atomic weights.
C = 51.27 / 12 = 4.27
H = 7.75 / 1 = 7.75
O = 40.98 / 16 =2.56
Step 2 : Divide all the answers with the smallest answer to get the subscripts for empirical formula.
C = 4.27/ 2.56 ≈ 2
H = 7.75/ 2.56 ≈ 3
O = 2.56 /2.56 = 1
Step 3: Construction of empirical formula by putting subscripts calculated in step 2.
Empirical formula form given data = 
Thus , subscript for H in the empirical formula for this compound is 3.
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