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kirill [66]
3 years ago
12

Guys i need help on this one

Chemistry
1 answer:
Dmitriy789 [7]3 years ago
4 0
This is a really hard one just tell your teacher its not like she/he will get mad for not doing one question and think you will get it
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6 C(s) + 3 H2(g) → 2 C6H6(l) Δ H = 49 kJ<br><br> TRUE or FALSE
VMariaS [17]

Answer:

True => ΔH°f for C₆H₆ = 49 Kj/mole

Explanation:

See Thermodynamic Properties Table in appendix of most college level general chemistry texts. The values shown are for the standard heat of formation of substances at 25°C. The Standard Heat of Formation of a substance - by definition - is the amount of heat energy gained or lost on formation of the substance from its basic elements in their standard state. C₆H₆(l) is formed from Carbon and Hydrogen in their basic standard states. All elements in their basic standard states have ΔH°f values equal to zero Kj/mole.

7 0
3 years ago
An atom has radius of 227 pm and crystallizes in a body-centered cubic unit cell. What is the volume of the unit cell
sdas [7]

We will see that the volume of the unit cell is 144,070,699.06 pm^3

<h3>How to get the volume of a body-centered cubic unit cell?</h3>

In a body-centered cubic unit cell, the side length of the cube is given as:

S = \frac{4}{\sqrt{3} } *R

Where R is the radius of the atom.

And the volume of a cube is the side length cubed, then we can see that the volume of our cube will be:

V = S^3 = (\frac{4}{\sqrt{3} }*227pm)^3

Solving that we get:

V  = (\frac{4}{\sqrt{3} }*227pm)^3 = 144,070,699.06pm^3

This is the approximated volume of the unit cell.

If you want to learn more about unit cell structures, you can read:

brainly.com/question/13110055

5 0
2 years ago
Difference between element and radical​
Romashka-Z-Leto [24]

Answer:

A radical is a group of atoms behaving as a unit in a number of compounds where as an element is a species of atoms having the same number of protons in their atomic nuclei.

Explanation:

6 0
3 years ago
Read 2 more answers
A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical
Katarina [22]

Answer:

empirical formula: H_2SO_4

2 g H

32.7 g S

65.3 g O

Explanation:

Like the problem said, the first thing we can do is calculate the mass of each of the 3 elements in a 100-gram sample:

- 2.00% * 100g = 2 g H

- 32.7% * 100g = 32.7 g S

- 65.3% * 100g = 65.3 g O

Now we need to find the empirical formula from these. To do so, convert all of those masses into moles by using the molar mass for each element:

- the molar mass of H is 1.01 g/mol

- the molar mass of S is 32.06 g/mol

- the molar mass of O is 16 g/mol

2 g H ÷ 1.01 g/mol = 1.98 mol H

32.7 g S ÷ 32.06 g/mol = 1.02 mol S

65.3 g O ÷ 16 g/mol = 4.08 mol O

Our ratio of H : S : O is now:

1.98 mol : 1.02 mol : 4.08 mol

Divide them all by the smallest number, which is 1.02:

1.98/1.02  :  1.02/1.02  :  4.08/1.02

1.94 : 1 : 4

1.94 ≈ 2

So:

2 : 1 : 4

Thus, the empirical formula is: H_2SO_4.

7 0
3 years ago
What is an example of turning chemical energy into light energy?
levacccp [35]
Chemical energy being changed into light energy would happen during phototsynthesis

5 0
4 years ago
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