<span>The volume in liters is </span>v=3.7xL
Answer:
The boiling point of 1-chlorobutane is substantially lower than that of 1-butanol
Explanation:
Fractional distillation is a separation process based on difference in boiling point of two compounds.
1-chlorobutane is a polar aprotic molecule due to presence of polar C-Cl bond. Hence dipole-dipole intermolecular force exists in 1-chlorobutane as a major force.
1-butanol is a polar protic molecule. Hence dipole-dipole force along with hydrogen bonding exist in 1-butanol.
Therefore intermolecular force is stronger in 1-butanol as compared to 1-chlorobutane.
So, boiling point of 1-butanol is much higher than 1-chlorobutane.
Hence mixture of 1-chlorobutane and 1-butanol can be separated by fractional distillation based on difference in boiling point.
So, option (D) is correct.
Answer:
0.960 m
Explanation:
Given data
- Mass of the solute: 27.9 g
- Molar mass of the solute: 233.2 g/mol
- Mass of the solvent: 125.0 g = 0.1250 kg
First, we will calculate the moles of solute.
27.9 g × (1 mol/233.2 g) = 0.120 mol
The molality of the compound is:
m = moles of solute / kilograms of solvent
m = 0.120 mol / 0.1250 kg
m = 0.960 m
Answer: Theoretically: Absolute Zero
Explanation:
which is about -273.15 degrees Celsius
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