The enzyme must attract substrates to its active state.
At the end of the reaction, products dissociate from the surface of the enzyme
The formula would be MgMn2O8
Answer: The volume of oxygen at STP is needed for complete given combustion is 1121.28 L.
Explanation:
The given reaction equation is as follows.
This shows that 2 moles of gasoline requires 25 moles of . Hence, moles of oxygen required to react with 4 moles of gasoline are calculated as follows.
At STP, the pressure is 1 atm and temperature is 273.15 K. Therefore, using ideal gas equation the volume of oxygen is calculated.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
Thus, we can conclude that volume of oxygen at STP is needed for complete given combustion is 1121.28 L.
Answer:
The correct answer is 4.58 grams.
Explanation:
Based on the Faraday's law of electrolysis, at the time of electrolysis, the amount of deposited substance is directly equivalent to the concentration of the flow of charge all through the solution. If current, I, is passed for time, t, seconds and w is the concentration of the substance deposited, then w is directly proportional to I*t or w = zIt (Here z refers to the electrochemical equivalent or the amount deposited when 1 C is passed).
For the reaction, n * 96500 C = molar mass
1C = molar mass/n*96500 = Equivalent wt / 96500
w = Equivalent wt / 96500 * I * t
In the given reaction,
Pb + PbO2 + 2HSO4- + 2H+ → 2PbSO4 + 2H2O, n = 2, the current or I drawn is 350 A, for time, t 12.2 seconds.
Now putting the values in the equation we get,
w = 207.19 / 2 * 96500 * 350 * 12.2 ( The molecular weight of Pb is 207.19 and the equivalent weight of Pb is 207.19 / 2)
w = 4.58 gm.
