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Yakvenalex [24]
3 years ago
6

The diagram below shows a light ray from a pencil hitting a mirror.

Physics
2 answers:
Alexxandr [17]3 years ago
8 0
Your correct answer is ray number 1

Hope this helps love! <3

Message me for more help.
max2010maxim [7]3 years ago
4 0

Answer:

1

Explanation:

Its 1 since the shape of it is more downwards which results the reflection going downwards.

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Two bulbs marked 200 W-250 V and 100 W-250 V are joined in
lozanna [386]

Answer:

<em>P = 66.67 W</em>

Explanation:

<u>Joule Heating</u>

It's the process by which the electric current passing through a conductor produces heat.

Also known as Joule's first law or the Joule–Lenz law, states that the power of heating generated by an electrical conductor (P) is proportional to the product of its resistance (R) and the square of the current (I).

It can be described by the equation that follows:

P = I^2.R

Also, we can calculate the voltage V with the formula of Ohm's law:

V = I.R

Combining both equations, power can be related to the voltage:

\displaystyle P=\frac{V^2}{R}

Given the power and the voltage, the resistance can be calculated by solving for R:

\displaystyle R=\frac{V^2}{P}

There are two bulbs marked P=200W V=250V and P=100 W V=250.

The first bulb has a resistance of:

\displaystyle R_1=\frac{250^2}{200}

\displaystyle R_1=312.5\Omega

The first bulb has a resistance of:

\displaystyle R_2=\frac{250^2}{100}

\displaystyle R_1=625\Omega

When connected in series, the total resistance is

R = R_1 + R_2=312.5\Omega+625\Omega

R=937.5\Omega

The total power consumed when connecting them to a V=250 V supply is:

\displaystyle P=\frac{250^2}{937.5}

P = 66.67 W

4 0
3 years ago
At highway speeds, a particular car is capable of an acceleration of about 1.6 m/s?. At this rate,
kicyunya [14]

Given parameters:

Acceleration of the car = 1.6m/s

Initial speed  = 80km/hr

Final speed  = 110km/hr

Solution:

Time taken to achieve this speed = ?

Solution:

Acceleration is the rate of change of velocity with the time taken.

  Mathematically;

     a  = \frac{V - U}{T}

where a is the acceleration

           V is the final velocity

           U is the initial velocity

           T is the time taken

Now make the unknown time the subject of the expression;

      aT  = V - U

         T = \frac{V - U}{a}  

Convert the given acceleration to km/hr;

       1.6m/s  = 1.6 x \frac{m}{s}  x \frac{1km}{1000m} x \frac{3600s}{1hr} = 5.76km/hr

Input the parameters and solve;

       T = \frac{110 - 80}{5.76}  = 5.2hrs

The time taken is 5.2hrs

5 0
4 years ago
The path of a projectile fired at a 30° angle to the horizontal best described as ?
STALIN [3.7K]
Linear.

Since it is fired at a 30-degree angle, it is assumed to follow a straight line, which makes it linear.
6 0
4 years ago
Two samples of aluminum foil, 27 grams and 54 grams, are cut out from a roll. Which of the following properties is different for
Delicious77 [7]
Before answering this question, you must know the concept between extensive and intensive property. The extensive property does not depend on the amount of substance (like mass), which is the opposite of intensive properties. From the given choices, the rest are extensive properties except for <em>amount of matter</em>. Hence, that is the answer.
4 0
4 years ago
Read 2 more answers
A 40 kg slab rests on a frictionless floor. A 10 kg block rests on top of the slab. The coefficient of static friction between t
Wewaii [24]

Answer:

a) a = 6.1 m/s^2

b)  a = 0.98m/s^2

Explanation:

Mass of slab = 40kg

Mass of block = 10kg

Coefficient of static friction (Us)  = 0.60

Kinetic coefficient (UK)  = 0.40

Horizontal force = 100N

The normal reaction from 40kg slab on 10 kg block = 10*9.81

= 98.1N

Static frictional force = Us*R

= 98.1*0.6

= 58.86N

This is less than the force applied

If 10 kg block will slide on the 40 kg slab,  net force = 100 - kinetic force

Kinetic force (Uk*R) = 0.4*98.1

= 39.28N

= 39N

Net force = 100 -39

= 61N

Recall that F = ma

For 10 kg block

a = F/m

a = 61/10

a = 6.1m/s^2

b) Frictional force on 40 kg slab by 10 kg = 98.1*0.4

= 39.24

= 39N

F = ma

a = F/m

For 40kg slab

a = 39/40

a = 0.98m/s^2

3 0
3 years ago
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