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Delvig [45]
2 years ago
12

Annika has a circular garden with a radius of 14 feet. One fourth of the garden is planted with yellow roses. what is the area n

ot planted in yellow roses? Use 22/7 for pi.
Mathematics
1 answer:
Brilliant_brown [7]2 years ago
4 0

Answer:A

Step-by-step explanation:

3/4*22/7*14^2

=3/4*22/7*14*14

=3*11*2*7

=33*2*7

=66*7

=462

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Using the method of substitution solve the problem need help completely loss if you can do it quickly it would help
miv72 [106K]
Equation 1)  y=x+3
Equation 2)  y=2x+5

Rearrange both equations so that (x) and (y) are on the same side.

1) -x+y=3
2) -2x+y=5

Subtract equations with each other.

x=-2

Plug in -2 for (x) in equation 1.

y=(-2)+3

Simplify.

y=1

(-2, 1)

~Hope I helped!~
3 0
2 years ago
4.
makkiz [27]

Answer:

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Step-by-step explanation:

fuсk you fuсk you fuсk you fuсk you fuсk you

7 0
2 years ago
Frankie buys some stamps.
bezimeni [28]

Answer:

22

Step-by-step explanation:

£9.90 = 990p

x is number of 50p stamps

2x* 20 + x* 50 = 990

40x+50x = 990

90x = 990

x = 11

2x = 22

11 50p stamps

22 20p stamps

check:

11*50+22*20 = 550 + 440 = 990

4 0
2 years ago
Twice a certain number is tripled. what is the resulting number
saveliy_v [14]

Answer:

Twice a certain number is tripled:

2*x*3

= 6x

7 0
2 years ago
The weights of college football players are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds
Roman55 [17]

Answer:

The probability that he weighs between 170 and 220 pounds

P( 170 ≤ x≤ 200) = 0.3811

Step-by-step explanation:

<u><em>Explanation:</em></u>-

Given mean of the Population = 200 pounds

Given standard deviation of the Population = 50 pounds

Let 'X' be the random variable of the weights of college football players are normally distributed.

Let   x₁ = 170

Z_{1} = \frac{x_{1} - mean}{S.D}

Z_{1} = \frac{170 - 200}{50}= -0.6

Let   x₂ = 220

Z_{2} = \frac{x_{2} - mean}{S.D}

Z_{2} = \frac{220 - 200}{50}= 0.4

<em>The probability that he weighs between 170 and 220 pounds.</em>

<em>P( 170 ≤ x≤ 200) = P(Z₁ ≤z≤Z₂)</em>

                          =  P(-0.6 ≤z≤0.4)

                          = P(z≤0.4)-P(z≤-0.6)

                         =  0.5 + A(0.4) -(0.5 - A(-0.6)

                        =   A(0.4) + A(0.6)       A(-z) = A(z)

                       = 0.1554 +0.2257   ( check<em> Areas in normal table)</em>

<em>                       = 0.3811</em>

<u><em>Conclusion</em></u><em>:-</em>

<em>The probability that he weighs between 170 and 220 pounds</em>

<em>P( 170 ≤ x≤ 200) = 0.3811</em>

7 0
2 years ago
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