1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dahasolnce [82]
3 years ago
9

Which of these is a key feature of an experimental study?

Physics
2 answers:
Pavlova-9 [17]3 years ago
7 0
The key feature in the experimental study is C. <span>The treatment in the experiment must be applied to each of the individuals in the experimental group. This is because it is made sure that the variables and conditions in different correspondents are applied so that actual results may be concluded.</span>
juin [17]3 years ago
3 0

the only logical answer is C


You might be interested in
Which term refers to a variable that a scientist adjusts during an experiment?
azamat

Answer:

it’s c

Explanation:

5 0
2 years ago
A rectangular loop of area A is placed in a region where the magnetic field is perpendicular to the plane of the loop. The magni
mina [271]

Answer:

Induced emf, \epsilon=-A\dfrac{B_{max}e^{-t/\tau}}{\tau}

Explanation:

The varying magnetic field with time t is given by according to equation as :

B=B_{max}e^{-t/\tau}

Where

B_{max}\ and\ t are constant

Let \epsilon is the emf induced in the loop as a function of time. We know that the rate of change of magnetic flux is equal to the induced emf as:

\epsilon=-\dfrac{d\phi}{dt}

\epsilon=-\dfrac{d(BA)}{dt}

\epsilon=-A\dfrac{d(B)}{dt}

\epsilon=-A\dfrac{d(B_{max}e^{-t/\tau})}{dt}

\epsilon=A\dfrac{B_{max}e^{-t/\tau}}{\tau}

So, the induced emf in the loop as a function of time is A\dfrac{B_{max}e^{-t/\tau}}{\tau}. Hence, this is the required solution.

7 0
2 years ago
Which options correctly describe the velocity of the object represented in the graph?
kirza4 [7]
There is no graph ...
7 0
2 years ago
Which of the following has to happen before the eardrum begins to vibrate with the same frequency as the source of the sound wav
777dan777 [17]
I just took the test it is D




I am 100% sure
8 0
3 years ago
Read 2 more answers
State Newton's three laws of motion.​
tresset_1 [31]

Answer:

Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Newton's second law states that the acceleration of an object is directly related to the net force and inversely related to its mass. Acceleration of an object depends on two things, force and mass.

Newton's third law states that if an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.

Explanation:

6 0
3 years ago
Other questions:
  • Bob has a brother, jim, who has a daughter named bertha. Bertha's daughter, jennifer, has a sister named penny. which of the fol
    5·2 answers
  • There are many risks associated with nuclear power. Which is NOT a risk associated with nuclear power?
    14·2 answers
  • A net force of 16 N causes a mass to accelerate at a rate of 5 m/s^2. Determine the mass.
    15·1 answer
  • Which is the relationship between photon energy and the color of light?
    6·1 answer
  • The compound limestone (which is mined in Crossville) is chemically
    15·1 answer
  • What energy happens when you plug in a blender?
    7·2 answers
  • A rat is pushed with a massive force. The mass of the rat is 2.3 kg and the acceleration of the rat is 9.5 m/s^2. What was the f
    5·1 answer
  • A cyclist reaches the top of a hill with
    10·1 answer
  • Marx argued that what happens when a worker is separated
    12·1 answer
  • What happens to temperature of a substance during phase change
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!