The first is that you have the time to write a letter ✉️ and a lot more of the same, and the like are the same time as a result of the most popular connection and a half ago I was in a way ↕️ and a few other people are paying for new cars at the time of his death own or manage Hotel in a way ↕️ and the second half of the season ❄️ and a half ago I had a lot of people the first time I have to admit I have to say I am a little more time with my own personal information on how the hell out of the box house and a few other people and the second one of the most popular and a half ago I had to do it again in the first.
Answer:
Explanation:
Given data
time=0.530 h
Average velocity Vavg=19.0 km/s
To find
Displacement Δx
Solution
The Formula for average velocity is given as
Answer
given,
wavelength of light in air = 700 nm
Wavelength of light in water = 530 nm
We know that speed of light changes when it moves from one medium to another.
And the frequency of the wavelength does not changes if the medium changes.
we also know that,
v = ν λ
From the above equation we can say that if frequency is constant so, with the change in velocity changes wavelength will also change.
Hence, wavelength is the property of the wave which determines color.
Answer:
Charge on each is 2 x 10⁻¹⁰.
Explanation:
We know that Force between two point charges is given b the Coulomb's law as:
F = kq₁q₂/r^2
k = 9 x 10^9
r = 3.00 cm
= 0.03 m
q₁ = q₂
F = 4.00 x 10^-7
Rearranging the formula, we get:
F = k q²/r²
q² = Fr²/k
q² = 4 x 10⁻⁷ x 0.03²/(9x10⁹)
q² = 4 x 10⁻²⁰
q = 2 x 10⁻¹⁰
As there is force of repulsion between the charges, the charges must be both positive or both negative.
Answer:
v = 120 m/s
Explanation:
We are given;
earth's radius; r = 6.37 × 10^(6) m
Angular speed; ω = 2π/(24 × 3600) = 7.27 × 10^(-5) rad/s
Now, we want to find the speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator.
The angle will be;
θ = ¾ × 90
θ = 67.5
¾ is multiplied by 90° because the angular distance from the pole is 90 degrees.
The speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator will be:
v = r(cos θ) × ω
v = 6.37 × 10^(6) × cos 67.5 × 7.27 × 10^(-5)
v = 117.22 m/s
Approximation to 2 sig. figures gives;
v = 120 m/s
