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Butoxors [25]
3 years ago
12

List some ways houses would be built differently if gravity were much stronger or much weaker ?two

Physics
2 answers:
tia_tia [17]3 years ago
8 0

Answer:

If gravity were stronger, houses and buildings would have to be more sturdy so they do not get crushed to the ground. If gravity were weaker, buildings and houses would have to be built stronger so they do not float away.

Hope this helps you!

Serggg [28]3 years ago
3 0
If gravity where much weaker, then the houses wouldn’t need as much structural support, and then could be built as much more taller as they wouldn’t go through as much stress. and if gravity was stronger, buildings would need to be a lot more structurally sound and wouldn’tbe able to maintain a tall structure as the force of gravity would be too much for them
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Babe Ruth steps to the plate and casually points to left centerfield to indicate the location of his next home run. Themighty Ba
Elden [556K]

Answer:

Fs = 32N

Fh = 21 N

Explanation:

Statics

Let Fs be the force of the shoulder, assumed upward

Let Fh be the force of the hand, assumed downward

Sum moments about the hand to zero

1.1(9.8)[67] - Fs[22.5] = 0

Fs = 32N

Sum vertical forces to zero

32 - Fh - 1.1(9.8) = 0

Fh = 21 N

Or we could sum moments about the shoulder point

1.1(9.8)[67 - 22.5] - Fh[22.5] = 0

Fh = 21 N

6 0
3 years ago
Two 5.0-g aluminum foil balls hang from 1.0-m-long threads that are suspended from the same point at the top. The charge on each
Allisa [31]

Answer: F=0.075N

Explanation:

T*cos(θ) = mg=0.005X9.8

T*cos(θ)=0.049N

T = 0.049/cosθ

F = k*q1*q2 / r2

F = 8.9875 * 10^9 * q1*q2 / r^2 q1

F = 8.9875 * 10^9 * (5 x 10^-6)^2 / r^2

F=0.2246875/r^2

r= 2Lsinθ = 2 x 1 x sinθ =2sinθ

Kindly check the attached for further solution

5 0
3 years ago
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Serjik [45]

Answer:

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Explanation:

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5 0
3 years ago
find the coefficient of kinetic friction for a 10 kg box being dragged steadily across the surface with a force of 2.0 Newtons​
Mazyrski [523]

Answer:

0.02

Explanation:

Force, F=\mu_k N where N is normal reaction and coefficient of kinetic friction is \mu_k. Also, N is equivalent to mg ie N=mg where m is mass of an object and g is acceleration due to gravity. Making \muthe subject of the formula then

\mu_k=\frac {F}{mg}

Substituting F with 2 N, m with 10 kg and g with 9.81 then

\mu_k=\frac {2}{10\times 9.81}=0.0203873598369\approx 0.02

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4 years ago
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arlik [135]

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