Answer:
Fs = 32N
Fh = 21 N
Explanation:
Statics
Let Fs be the force of the shoulder, assumed upward
Let Fh be the force of the hand, assumed downward
Sum moments about the hand to zero
1.1(9.8)[67] - Fs[22.5] = 0
Fs = 32N
Sum vertical forces to zero
32 - Fh - 1.1(9.8) = 0
Fh = 21 N
Or we could sum moments about the shoulder point
1.1(9.8)[67 - 22.5] - Fh[22.5] = 0
Fh = 21 N
Answer: F=0.075N
Explanation:
T*cos(θ) = mg=0.005X9.8
T*cos(θ)=0.049N
T = 0.049/cosθ
F = k*q1*q2 / r2
F = 8.9875 * 10^9 * q1*q2 / r^2 q1
F = 8.9875 * 10^9 * (5 x 10^-6)^2 / r^2
F=0.2246875/r^2
r= 2Lsinθ = 2 x 1 x sinθ =2sinθ
Kindly check the attached for further solution
Answer:
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Explanation:
The first two are already answered 5-9 I cannot answer because I have not watched "October sky video" and I don't know who homer and the boys are<em>.</em>
I Hope This helps
Answer:
0.02
Explanation:
Force,
where N is normal reaction and coefficient of kinetic friction is
. Also, N is equivalent to mg ie N=mg where m is mass of an object and g is acceleration due to gravity. Making
the subject of the formula then

Substituting F with 2 N, m with 10 kg and g with 9.81 then

Answer:
the answer is A because it has the least number but high in energy