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OLga [1]
3 years ago
11

Symbol for the magnesium oxide reactants​

Chemistry
2 answers:
Stella [2.4K]3 years ago
8 0

Answer:

MgO

Explanation:

Magnesium oxide is formed up of the ions Mg2+ and O2

andreyandreev [35.5K]3 years ago
8 0

Answer:

MgO

Explanation:

Mg2 + O2 is MgO, have a nice day

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A particle accelerates from rest with an acceleration of 8.0m/s2. Calculate its velocity after 150s. What kinematic formula must
Ipatiy [6.2K]

<u>Answer</u>:

Final velocity: 1200 m/s

<u>Explanation</u>:

Formula:   \overline{a} = \frac{v - v_0}{t} = \frac{\Delta v}{\Delta t}

<u>Where</u>:

a = average acceleration

v = final velocity

vo = starting velocity

t = elapsed time

<em>Here the final velocity is unknown which we have to find. The initial is 0 m/s</em>

<em>as it was at rest. The time taken: 150 seconds. Acceleration given 8.0 m/s²</em>

using the formula:

\overline{a} = \frac{v - v_0}{t}

8 = \frac{v - 0}{150}

v = 1200 m/s

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How is the mass of carbon related to the mole?
Anuta_ua [19.1K]

Answer:

Simply put, you can go from moles to grams and vice versa by using the mass of 1 mole of that substance, i.e its molar mass. For example, the molar mass of carbon is 12.011 g/mol. This means that 1 mole of carbon, or 6.022⋅1023 atoms of carbon, weigh 12.011 g.

Explanation:

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4 years ago
Give 1 example of a chemical reaction that is involved in coral<br> bleaching.
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2HCO3 - + Ca2+ CaCO3 + CO2 + H2O Bicarbonate (HCO3-) combines with calcium ions in the water to make calcium carbonate (CaCO3, limestone). This process can occur both within organisms such as corals or as a simple chemical reaction in the water itself.
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The following data were obtained in a kinetics study of the hypothetical reaction A + B + C → products. [A]0 (M) [B]0 (M) [C]0 (
Vladimir [108]

Answer:

B. First order, Order with respect to C = 1

Explanation:

The given kinetic data is as follows:

A + B + C → Products

     [A]₀     [B]₀    [C]₀       Initial Rate (10⁻³ M/s)

1.   0.4      0.4     0.2       160

2.  0.2      0.4      0.4       80

3.   0.6     0.1       0.2       15

4.   0.2     0.1       0.2        5

5.   0.2     0.2      0.4       20

The rate of the above reaction is given as:

Rate = k[A]^{x}[B]^{y}[C]^{z}

where x, y and z are the order with respect to A, B and C respectively.

k = rate constant

[A], [B], [C] are the concentrations

In the method of initial rates, the given reaction is run multiple times. The order with respect to a particular reactant is deduced by keeping the concentrations of the remaining reactants constant and measuring the rates. The ratio of the rates from the two runs gives the order relative to that reactant.

Order w.r.t A : Use trials 3 and 4

\frac{Rate3}{Rate4}= [\frac{[A(3)]}{[A(4)]}]^{x}

\frac{15}{5}= [\frac{[0.6]}{[0.2]}]^{x}

3 = 3^{x} \\\\x =1

Order w.r.t B : Use trials 2 and 5

\frac{Rate2}{Rate5}= [\frac{[B(2)]}{[B(5)]}]^{y}

\frac{80}{20}= [\frac{[0.4]}{[0.2]}]^{y}

4 = 2^{y} \\\\y =2

Order w.r.t C : Use trials 1 and 2

\frac{Rate1}{Rate2}= [\frac{[A(1)]}{[A(2)]}]^{x}[\frac{[B(1)]}{[B(2)]}]^{y}[\frac{[C(1)]}{[C(2)]}]^{z}

we know that x = 1 and y = 2, substituting the appropriate values in the above equation gives:

\frac{160}{80}= [\frac{[0.4]}{[0.2]}]^{1}[\frac{[0.4]}{[0.4]}]^{2}[\frac{[0.2]}{[0.4]}]^{z}

1 = (0.5)^{z}

z = 1

Therefore, order w.r.t C = 1

8 0
4 years ago
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