setup 1 : to the right
setup 2 : equilibrium
setup 3 : to the left
<h3>Further explanation</h3>
The reaction quotient (Q) : determine a reaction has reached equilibrium
For reaction :
aA+bB⇔cC+dD
![\tt Q=\dfrac{C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=%5Ctt%20Q%3D%5Cdfrac%7BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
Comparing Q with K( the equilibrium constant) :
K is the product of ions in an equilibrium saturated state
Q is the product of the ion ions from the reacting substance
Q <K = solution has not occurred precipitation, the ratio of the products to reactants is less than the ratio at equilibrium. The reaction moved to the right (products)
Q = Ksp = saturated solution, exactly the precipitate will occur, the system at equilibrium
Q> K = sediment solution, the ratio of the products to reactants is greater than the ratio at equilibrium. The reaction moved to the left (reactants)
Keq = 6.16 x 10⁻³
Q for reaction N₂O₄(0) ⇒ 2NO₂(g)
![\tt Q=\dfrac{[NO_2]^2}{[N_2O_4]}](https://tex.z-dn.net/?f=%5Ctt%20Q%3D%5Cdfrac%7B%5BNO_2%5D%5E2%7D%7B%5BN_2O_4%5D%7D)
Setup 1 :

Q<K⇒The reaction moved to the right (products)
Setup 2 :

Q=K⇒the system at equilibrium
Setup 3 :

Q>K⇒The reaction moved to the left (reactants)
D. uranium: atomic number 92, mass 238, neutrons 146
238-92=146
Noble means chemically inert.
That is one way.
It is group 8 and doesn't react with atoms because it is stable.<span />
Answer:
Mass defect = - 0.060238 amu
Explanation:
To calculate the mass defect:
1. add up the masses of each proton and of each neutron that make up the nucleus,
Berylium 9 has;
4 protons = 4 * 1.00728 amu = 4.02912 amu
5 Neutrons = 5 * 1.00866 amu = 5.0433 amu
Sum = 9.07242 amu
2. subtract the actual mass of the nucleus from the combined mass of the components to obtain the mass defect.
Mass defect = Actual Mass - Combined mass
Mass defect = 9.012182 amu - 9.07242 amu
Mass defect = - 0.060238 amu