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Mariulka [41]
2 years ago
13

Please help will give brainliest to right answer!!

Chemistry
2 answers:
Leno4ka [110]2 years ago
4 0
A…………………………………………………..
Nezavi [6.7K]2 years ago
3 0

Answer:

C

Explanation:

NP

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Isoelectric point. The isoelectric point (pI) is the pH at which a molecule has no net charge. The amino acid glycine has two io
timama [110]

Answer:

pI = 6.16

Explanation:

The pI is given by the average of the pKas that are involved. In this case,

Pka of carboxylic acid was given as 2.72 and that of the Amino group was given as 9.60. the average would then be ½(2.72+9.60)

= 6.16

6 0
3 years ago
Seawater has a ph of 8.1. what is the concentration of oh–?
lara31 [8.8K]
PH scale is used to determine how acidic or basic a solution is.
pH can be calculated as follows;
by knowing the ph we can calculate pOH
pH + pOH = 14
pOH = 14 - 8.1 
pOH = 5.9 
pOH is used to calculate the hydroxide ion concentration 
pOH = -log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 1.26 x 10⁻⁶ M
therefore hydroxide ion concentration is 1.26 x 10⁻⁶ M
4 0
3 years ago
C6H12O6 + 6O2 → 6CO2 + 6H2O is the chemical equation for cellular respiration. What are the products in this reaction?
maks197457 [2]

Answer:

The products are: A) CO2, H2O

Explanation:

Those products that are seen on the right side of the reaction (that is, those substances that are generated from the reagents). In this case they are carbon dioxide and water.

The general equation of cellular respiration is:

C6H1206 + 602 -> 36 ATP + 6CO2 + 6H20

4 0
3 years ago
A phosphate buffer is involved in the formation of urine. The developing urine contains H2PO4 and HPO42- in the same concentrati
Katen [24]

Answer:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

Explanation:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.

The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,

Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}

The pKa is

-Log (Ka) = -Log (6.2x10^{-8}) = 7.2

The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.

In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.

If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1)  moves to the left neutralizing the excess proton concentration.

3 0
3 years ago
State the number of protons, electrons and neutron ​
skad [1K]

Answer:

You didn't show which element it is. The proton is the atomic number, the electron is the same number of protons, and the neutron is the atomic mass rounded to the nearest whole number minus the proton.

Explanation:

4 0
3 years ago
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