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2 years ago

5

There are 21 animals living in the barn. Some are chickens and some are horses. There are 46 legs in all. How many chickens and

how many horses are in the barn?

1 answer:

astra-53 [7]2 years ago

8 0

Answer:

7 horses,and 6 chickens

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Explain the steps you would take to complete this conversion problem.

ohaa [14]

I would multiply 46x1x1,000 to get 46,000. the. i would multiply 1x2.2x1 to get 2.2. i would then divide 46,000/2.2 to get 20,909.0909

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2 years ago

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What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

<u>Find the length of the segment DC</u>

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

<u>the answer is</u>

$BC=31.2\ units$

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2 years ago

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Type the correct answer in the box

algol13

c = cost of food/med for cats

d = cost of food/med for dog

y = total cost/spent

What you know:

y = 6c + d [has 6 cats and 1 dog]

c = 2/3d - 5 [cost for cat is 5 less than 2/3 cost for dog]

y = $195

y = 6c + d

Substitute/plug in what you know, plug in (2/3d - 5) for c and 195 for y

195 = 6(2/3d - 5) + d Distribute/multiply 6 into (2/3d - 5)

195 = 4d - 30 + d Combine like terms

195 = 5d - 30 Add 30 on both sides of the equation

225 = 5d Divide 5 on both sides

$45 = d

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3 years ago

steve measured the length of his room and found it to be 9 feet and 6 inches. The width of his room was 11 feet exacly. What is

Art [367]

Length: 114 in.
Width: 132 in.

For length, you have 9 feet and 6 inches. Meaning that if you would want to get the length of his room in inches, you would have to multiply 9 with 12 and add 6.

It's the same thing for the width.

If you need more help comment below!

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Number equal distance from zero but on different sides of zero

Kay [80]

Are you asking for definition because if so i believe what you’re looking for is absolute value

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3 years ago