The question is asking which formula will give the results
1, 9, 36, 100, 225, ...
for k values of
1, 2, 3, 4, 5, ...
You can try them out to see.
A) for k=2, gives 2*3/2 = 3 . . . not 9
B) for k=1, gives 2^3/3 = 8/3 . . . not 1
C) for k=2, gives (2^2*3^2)/4 = 9 . . . . looks promising
D) for k=1, gives 1*2^3/5 = 8/5 . . . not 1
Selection C is the only viable choice. (And the correct one.)
First question:
I urge you to perform the division using the synthetic division method:
________________
-4 / 1 3 -6 -6 8
-4 4 8 -8
-----------------------
1 -1 -2 2 0
Note that there is no remainder. When this is the case, the divisor (here, that's -4) is a root of the given polynomial, and the value of that polynomial, g(-4), is 0.
If the remainder were not 0, then the remainder represents the value of the polynomial for that particular divisor. For example, if x = -3, the remainder is -28. We'd write that as g(-3) = -28.
But here, g(-4) = 0.
Answer: 3.5
Step-by-step explanation:
2.10/0.6=3.5
3.5x0.6=2.10
Answer:
Step-by-step explanation:
Check the attachment the solution of the work is given there
Answer:
p=7Q/2
Step-by-step explanation:
Original number of students:
p students to do 1 job in 25 days.
Let r= the rate for 1 student.
pr*25=1
pr*25=1 is the work rate equation for p students.
Lesser number of students:
p-Q students came to do the job and time required was 35 days.
(P-Q)*r*35=1.
The unknowns are p, Q and r
Equate the original number of students and the lesser number of students
pr*25=(P-Q)*r*35
25rp=35rp - 35Qr
Collect like terms
25rp-35rp = -35Qr
Divide both sides by -5
-5rp+7rp=- 7rp
It can be re written as
7rp-5rp=-7Qr
2rp=7Qr
Make p the subject of the formula
p=7Qr/2r
p=7Q/2
p=7Q/2 is the original number of students
-10rp = -35Qr
The system of these two equations can be solved for p. See the THREE unknown
variables, p, r, and Q. You might assume that either r or Q would be a constant.
