=10-10i
Explanation:
3-4i+7-6i
(Add 3 and 7)
(Add -4i and -6i)
Put together
10-10i
Answer:
the no of liters required is 50.55 liters
Step-by-step explanation:
Given that
The car gas efficiency is 23.0 mi/gal
distance is 495 km
1 gal = 3.78 L
1 km = 0.6214 mi
We need to find out the no of liters of gas that would needed to complete a trip
So,
= (495 × 3.78 × 0.6214) ÷ (23)
= 50.55 Liters
hence, the no of liters required is 50.55 liters
6-4.2=1.8
The percent of change from 1982 to 1999 is:
(1.8/4.2)*100=42.86%
Answer:
4/5
Step-by-step explanation:
1. Do 1/2 x 0.6 which is 0.3 or 3/10
2. Add 3/10 to 1/2 which is 4/5
Let a be the first term and d be the common difference
t5 = 3 = a + 4d
t7 = 7 = a + 6d
a + 6d - a - 4d = 7 - 3
2d = 4
d = 2
Sub d = 2,
3 = a + 4(2)
a = -5
t2 = a + d
t2 = -5 + 2
t2 = -3
