Answer:
304 meters downstream
Explanation:
The given parameters are;
The speed of the swimmer = 2.00 m/s
The width of the river = 73.0 m
The speed of the river = 8.00 m/s
Therefore;
The direction of the swimmer's resultant velocity = tan⁻¹(8/2) ≈ 75.96° downstream
The distance downstream the swimmer will reach the opposite shore = 4 × 73 = 304 m downstream
The distance downstream the swimmer will reach the opposite shore = 304 m downstream
Answer:
The maximum electric field strength = 0.01 V/m
Explanation:
Given
ΔV(max) = 4.00 mV = 0.004 V
d = 0.400 m
f = 1.00 Hz
Maximum electric field = (maximum potential)/(length)
Maximum electric field = E(max)
Maximum potential = 4.00 mV = 0.004 V
Length = 0.400 m
E(max) = (0.004/0.4) = 0.01 V/m
Hope this Helps!!!
da answer is liquiddddddddd
The range of the projectile is 188 m
Explanation:
The motion of the arrow in this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
The path of a projectile is the combination of these two motions: see figure in attachment.
In order to find the horizontal range of the projectile, we just need to calculate the horizontal distance travelled.
We have:
t = 5.0 s (time of fligth of the projectile)
and the horizontal velocity is constant, and it is given by

where
is the initial velocity
is the angle of projection
Substituting,

And therefore, the range of the projectile is:

Learn more about projectile motion:
brainly.com/question/8751410
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Answer:
we know that current = charge/time
Explanation:
therefore,
A = 8000/120
A => 66.666.... amperes