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3 years ago

Which of the following are Cations? (Select all that apply)

Chemistry

1 answer:

AleksandrR [38]3 years ago

5 0

Answer:

k(+)

NH4(+)

Al3(+)

Explanation:

cations are those elements who donate their electrons and we put a positive charge on it and receivers get negative charge and they are called anion.....Thank you so,much Please let me know how you feel and is helps you or not....

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Which best describes a mixture?

natali 33 [55]

Answer:

I think the answer would be b, sorry if I'm wrong(EDIT: ITS ACTUALLY AAAAA)

5 0

2 years ago

If the mass of an object is 60.0 grams and the density of the object is 15.0 g/mL, what is the volume of the object? The formula

laila [671]

Answer:

168.56 mL

Explanation:

density = mass/volume, use basic algebra skills to replace the volume and solve

7 0

2 years ago

Explain the process of how James Chadwick found the neutron.

Andrews [41]

Answer:

Discovery of neutron

Explanation:

Until 1932, the atom was believed to be composed of a positively charged nucleus surrounded by negatively charged electrons, after successful discovery of electron by J.J. Thompson and proton by Ernest Rutherford.

In 1932, James Chadwick bombarded beryllium atoms with alpha particles.

As Chadwick had previously seen in experiment conducted by Frédéric and Irène Joliot-Curie, they had bombarded a sample of beryllium with alpha radiation.

Chadwick repeated the experiment and observed an unknown radiation, this showed no deflection what-so-ever.

He repeated this experiment by bombarding other materials, like helium, nitrogen and lithium,

Finally, Chadwick found that this radiation was composed of particles with a neutral electrical charge and had approximate mass of a proton.

This particle was then known as the neutron.

3 0

3 years ago

Question 21

Vesna [10]

Answer:

Option B. 2.62g.

Explanation:

We'll begin by calculating the masses of AgNO3 and NaCl that reacted and the mass of AgCl produced from the balanced equation. This is illustrated below:

AgNO3(aq) + NaCl(aq) —> AgCl(s) + NaNO3(aq)

Molar mass of AgNO3 = 108 + 14 + (16x3) = 170g/mol

Mass of AgNO3 from the balanced equation = 1 x 170 = 170g

Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl from the balanced equation = 1 x 58.5 = 58.5g

Molar mass of AgCl = 108 + 35.5 = 143.5g/mol

Mass of AgCl from the balanced equation = 1 x 143.5 = 143.5g

Summary:

From the balanced equation above,

170g of AgNO3 reacted with 58.5g of NaCl to 143.5g of AgCl.

Next, we shall determine the limiting reactant. This can be obtain as follow:

From the balanced equation above,

170g of AgNO3 reacted with 58.5g of NaCl.

Therefore, 3.10g of AgNO3 will react with = (3.10 x 58.5)/170 = 1.07 g of NaCl

From the calculations made above,

only 1.07g out of 3.10g of NaCl given reacted completely with 3.10g of AgNO3.

Therefore, AgNO3 is the limiting reactant and NaCl is the excess reactant.

Now, we can calculate the mass of AgCl produced from the reaction of 3.10g of AgNO3 and 3.10g of NaCl as illustrated below:

In this case, the limiting reactant will be use as it will produce the maximum yield of AgCl since all of it is consumed in the reaction.

The limiting reactant is AgNO3 and the mass of AgCl produced can be obtained as follow:

From the balanced equation above,

170g of AgNO3 reacted to produce 143.5g of AgCl.

Therefore, 3.10g of AgNO3 will react to produce = (3.10 x 143.5)/170 = 2.62g of AgCl.

Therefore, 2.62g of AgCl were produced from the reaction.

5 0

3 years ago

What is the maximum number of moles of PH 3 that can be formed when 0.2 formed moles of phosphorus reacts with 4 moles of hydrog

podryga [215]

Answer:

The maximum number of moles of PH₃ that can be formed is 0.8 moles.

Explanation:

The balanced reaction is:

P₄ + 6 H₂ → 4 PH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

P₄: 1 mole
H₂: 6 moles
PH₃: 4 moles

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, you can use a simple rule of three as follows: If by stoichiometry of the reaction 6 moles of hydrogen react with 1 mole of phosphorus, 4 moles of hydrogen will react with how many moles of phosphorus?

$moles of phosphorus=\frac{4 moles of hydrogen*1 mole og phosphorus}{6moles of hydrogen}$

moles of phosphorus= 0.667

But 0.667 moles of phosphorus are not available, 0.2 moles are available. Since you have less moles than you need to react with 4 moles of hydrogen, phosphorus will be the limiting reagent.

Then you can apply the following rule of three: if by stoichiometry 1 mole of P₄ forms 4 moles of PH₃, 0.2 moles of P₄ will form how many moles of PH₃?

$moles of PH_{3} =\frac{0.2 moles of P_{4} *4 moles of PH_{3} }{1 mole of P_{4} }$

moles of PH₃= 0.8

The maximum number of moles of PH₃ that can be formed is 0.8 moles.

4 0

2 years ago