An object is dropped from a bridge. A second object is thrown downwards 1.0 s later. They both reach the water 20 m below at the
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Answer
given,
wavelength = λ = 18.7 cm
= 0.187 m
amplitude , A = 2.34 cm
v = 0.38 m/s
A) angular frequency = ?
angular frequency ,
ω = 2π f
ω = 2π x 2.03
ω = 12.75 rad/s
B) the wave number ,
C)
as the wave is propagating in -x direction, the sign is positive between x and t
y ( x ,t) = A sin(k x - ω t)
y ( x ,t) = 2.34 x sin(33.59 x - 12.75 t)
Answer:
89.45 v/v
Explanation:
Let's take the data:
First draw the amplifier circuit.
After the circuit, the voltage division rule can be used to compute the parameters:
The input section is computed like this:
The output section is computed like this
The product A gives
A = A×
×
Computing gives output voltage = 89.45 v/v