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mina [271]
3 years ago
8

An object is dropped from a bridge. A second object is thrown downwards 1.0 s later. They both reach the water 20 m below at the

same instant. What was the initial speed of the second object? Neglect air resistance.
Physics
1 answer:
Lerok [7]3 years ago
7 0
Answer:

Explanation:
Kinematics equation for first Object:

but:
The initial velocity is zero

it reach the water at in instant, t1, y(t)=0:


Kinematics equation for the second Object:
The initial velocity is zero

but:

it reach the water at in instant, t2, y(t)=0. If the second object is thrown 1s later, t2=t1-1=1.02s


The velocity is negative, because the object is thrown downwards
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Motion with constant acceleration CER lab report <br><br> Can someone help!!
victus00 [196]

Answer:

Fan Speed For Low Position vs Time Graph : The slope is curved and it increases as you go up . The points start off close but they spread out as the time increases.

Fan Speed For Medium Position vs Time Graph : The speed increases quicker than the graph for low speed. The graph is less curved than the one for low speed. Also, the points spread out faster than they did for low speed as the time increases.

Fan Speed For High Position vs Time Graph: The Graph has a smaller curve then the low and medium speed. Also , the points are the furthest apart. The slope is not as spaced out as it was for the rest of the speed graphs .

Explanation: I just finished the lab:)

8 0
3 years ago
After driving a portion of the route, the taptap is fully loaded with a total of 25 people including the driver, with an average
loris [4]

Answer:

0.4455 m

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

Total mass is

m=62\times 25+15\times 3+5\times 3+25\\\Rightarrow m=1635\ kg

Here the spring constant is not given so let us assume it as k=36000\ N/m

Here, the forces are balanced

mg=kx\\\Rightarrow 1635\times 9.81=36000\times x\\\Rightarrow x=\dfrac{1635\times 9.81}{36000}\\\Rightarrow x=0.4455\ m

The springs are compressed by 0.4455 m

3 0
4 years ago
Two boxers are fighting. Boxer 1 throws his 5 kg fist at boxer 2 with a speed of 9 m/s.
Sladkaya [172]

Answer:

0.001 s

Explanation:

The force applied on an object is equal to the rate of change of momentum of the object:

F=\frac{\Delta p}{\Delta t}

where

F is the force applied

\Delta p is the change in momentum

\Delta t is the time interval

The change in momentum can be written as

\Delta p=m(v-u)

where

m is the mass

v is the final velocity

u is the initial velocity

So the original equation can be written as

F=\frac{m(v-u)}{\Delta t}

In this problem:

m = 5 kg is the mass of the fist

u = 9 m/s is the initial velocity

v = 0 is the final velocity

F = -45,000 N is the force applied (negative because its direction is opposite to the motion)

Therefore, we can re-arrange the equation to solve for the time:

\Delta t=\frac{m(v-u)}{F}=\frac{(5)(0-9)}{-45,000}=0.001 s

4 0
3 years ago
The motion of as car is drawn is vi against th graph​
LenKa [72]
10 and 40 would be your answer i believe.
3 0
3 years ago
A 1.5m wire carries a 6 A current when a potential difference of 61 V is applied. What is the resistance of the wire?
Alisiya [41]

Resistance = (voltage) / (current)

For this piece of wire . . .

Resistance = (61 volts) / (6 Amperes)

Resistance = (61/6) (V/A)

<em>Resistance = (10 and 1/6) ohms</em>

Since you know the voltage and current, the length doesn't matter.

7 0
3 years ago
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