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konstantin123 [22]
3 years ago
8

A small car is traveling at a speed of 60 mph on the highway. In the next lane, a large passenger bus is traveling at the same s

peed. Which of the following is true?
A. The bus has more kinetic energy than the car.
B. The car has more kinetic energy than bus.
C. The car and the bus have potential energy, not kinetic energy.
D. The car and bus have the same amount of kinetic energy.
Physics
1 answer:
alina1380 [7]3 years ago
3 0

Answer:

A. The bus has more kinetic energy than the car.

Explanation:

Kinetic energy is the amount energy possessed by the body when in motion. Kinetic is given by the formula;

K.E = 1/2mv²,

where m is the mass of the body and v is the velocity of the body.

Kinetic energy therefore depends on the mass and the velocity of the body. In this case, the passenger bus has more kinetic energy at constant speed than the car since it has a larger mass.

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Which steps can be taken to translate the phrase “the height of a tree is increased by seven inches” into an algebraic expressio
ololo11 [35]

Answer:

Explanation:

height of tree = x

seven inches= 7

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2 years ago
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Masses are stacked on top of the block until the top of the block is level with the waterline. This requires 20 g of mass. What
Kobotan [32]

Answer:

Mass of the wooden Block is 20g.

Explanation:

The buoyant force equation will be used here

Buoyant Force= ρ*g*1/2V Here density used is of water

m*g= ρ*g*1/2V

Simplifying the above equation

2m= ρ*V Eq-1

Also we know from the question that

ρ*V = m + 0.020 Eq-2 ( Density = (Mass+20g)/Volume )

Equating Eq-1 & Eq-2 we get

2m = m+0.020

m = 0.020kg

m = 20g

6 0
2 years ago
A plane has a mass of 360,000 kg takes-off at a speed of 300 km/hr. i) What should be the minimum acceleration to take off if th
melomori [17]

Answer:

i) the minimum acceleration to take off is 22500 km/h²

ii) the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) required force that the engine must exert to attain acceleration is 625 kN

Explanation:

Given the data in the question;

mass of plane m = 360,000 kg

take of speed v = 300 km/hr = 83.33 m/s

i)

What should be the minimum acceleration to take off if the length of the runway is 2.00 km

from Newton's equation of motion;

v² = u² + 2as

we know that a plane starts from rest, so; u = 0

given that distance S = 2 km

we substitute

(300)² = 0² + ( 2 × a × 2 )

90000 = 4 × a

a = 90000 / 4

a = 22500 km/h²

Therefore,  the minimum acceleration to take off is 22500 km/h²

ii) At this acceleration, how much time would the plane need from starting to takeoff.

from Newton's equation of motion;

v = u + at

we substitute

300 = 0 + 22500 × t

t = 300 / 22500

t = 0.0133 hrs

Therefore, the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) What force must the engines exert to attain this acceleration

we know that;

F = ma

acceleration a = 22500 km/hr² = 1.736 m/s²

so we substitute

F = 360,000 kg × 1.736 m/s²

F =  624960 N

F = 625 kN

Therefore, required force that the engine must exert to attain acceleration is 625 kN

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3 years ago
A rocket takes off from Earth. It travels 825km in 75 seconds. What is the
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Answer:

11 km/s

Explanation:

v=s/t

v=825km/75s

v=11km/s

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