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Artemon [7]
3 years ago
8

In a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the met

al are held constant. Assuming that the light incident on the metal surface causes electrons to be ejected from the metal, what happens if the intensity of the incident light is increased?
Physics
2 answers:
Novosadov [1.4K]3 years ago
7 0

Answer:

Explanation:

When a light beam of suitable frequency falls on metal surface, the electrons from the metal surface ejects, this phenomenon is called photo electric effect and the particular minimum frequency is called cut off frequency or threshold frequency.

When the intensity of incident radiation increases, the photo electric current also increases.  

mixer [17]3 years ago
5 0

Answer:

The kinetic energy of the ejected electrons increases.

Explanation:

As we know that electrons are only ejected from a metal surface if the frequency of the incident light increases the work function of the metal. If the frequency of the incident light is less than the work function of the metal no matter how intense the beam the electrons will not be ejected from the surface.

Using conservation of energy principle we have

E_{incident}=h\nu +\frac{1}{2}mv^{2}

If we increase the intensity  of incident light the term on the LHS of the above equation increases this increase appears in the kinetic energy term in RHS of the equation since h\times \nu remains constant.

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EleoNora [17]

The units for G must be [N][m^2][kg^{-2}]

Explanation:

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

F is the force

G is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between the objects

We know that:

  • The units of F are Newtons (N)
  • The units of m_1,m_2 are kilograms (kg)
  • The units of r are metres (m)

So, we can rewrite the equation in terms of G, to find its units:

G=\frac{Fr^2}{m_1 m_2}=\frac{[N][m]^2}{[kg][kg]}=[N][m^2][kg^{-2}]

Learn more about gravitational force:

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5 0
2 years ago
Which of the following happens during cell division? Question 7 options: It becomes more difficult for the cell to get rid of wa
kolbaska11 [484]

Answer;

B. Each daughter cell receives its own copy of the parent cell's DNA.

Explanation;

Cell division is the process in which a parent cell divides, giving rise to two or more daughter cells. It is an essential biological process in many organisms.

There are two types of cell division. Mitosis is used for growth and repair and produces diploid cells identical to each other and the parent cell. Meiosis is used for sexual reproduction and produces haploid cells different to each other and the parent cell.

6 0
3 years ago
Describe one situation in which forces are created>
garri49 [273]
If the measurement is in joules then you can push something or pull something as long as you are moving the object. Formula: f*n force times newtons
7 0
3 years ago
A hydrogen atom in a galaxy moving with a speed of 6.65×106 m/???? away from the Earth emits light with a wavelength of 5.13×10−
Mumz [18]

Answer:

The observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m.

Explanation:

Given that,

The actual wavelength of the hydrogen atom, \lambda_a=5.13\times 10^{-7}\ m

A hydrogen atom in a galaxy moving with a speed of, v=6.65\times 10^6\ m/s

We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :

v=c\times \dfrac{\lambda_o-\lambda_a}{\lambda_a}

\lambda_o is the observed wavelength

\lambda_o=\dfrac{v\lambda_a}{c}+\lambda_a\\\\\lambda_o=\dfrac{6.65\times 10^6\times 5.13\times 10^{-7}}{3\times 10^8}+5.13\times 10^{-7}\\\\\lambda_o=5.24\times 10^{-7}\ m

So, the observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m. Hence, this is the required solution.

8 0
2 years ago
A train has a constant speed of 10 m/s around a track with a diameter of 45 m what is the centripal acceleration?
Bumek [7]

Answer:

a_{c}= 4.44\frac{m}{s}

Explanation:

When an object goes on a circular movement, it has a centripetal acceleration that always points toward the center of the circle, it is the responsible of the change of direction in the movement of the object. and that centripetal acceleration is related with the speed in the next way:

a_{c}=\frac{v^{2}}{r}, with v the speed, r the radius of the track that is half of the diameter (22.5 m)

a_{c}=\frac{10^{2}}{22.5}

a_{c}= 4.44\frac{m}{s}

5 0
3 years ago
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