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Artemon [7]
4 years ago
8

In a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the met

al are held constant. Assuming that the light incident on the metal surface causes electrons to be ejected from the metal, what happens if the intensity of the incident light is increased?
Physics
2 answers:
Novosadov [1.4K]4 years ago
7 0

Answer:

Explanation:

When a light beam of suitable frequency falls on metal surface, the electrons from the metal surface ejects, this phenomenon is called photo electric effect and the particular minimum frequency is called cut off frequency or threshold frequency.

When the intensity of incident radiation increases, the photo electric current also increases.  

mixer [17]4 years ago
5 0

Answer:

The kinetic energy of the ejected electrons increases.

Explanation:

As we know that electrons are only ejected from a metal surface if the frequency of the incident light increases the work function of the metal. If the frequency of the incident light is less than the work function of the metal no matter how intense the beam the electrons will not be ejected from the surface.

Using conservation of energy principle we have

E_{incident}=h\nu +\frac{1}{2}mv^{2}

If we increase the intensity  of incident light the term on the LHS of the above equation increases this increase appears in the kinetic energy term in RHS of the equation since h\times \nu remains constant.

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When an object is fully converted into energy the amount of energy liberated is
EleoNora [17]

Answer:

Mass, m = 4 kg

Explanation:

<u>Given the following data;</u>

Energy = 3.6 * 10^17 Joules

We know that the speed of light is equal to 3 * 10⁸ m/s.

To find the mass of the substance;

The theory of special relativity by Albert Einstein gave birth to one of the most famous equation in science.

The equation illustrates, energy equals mass multiplied by the square of the speed of light.

Mathematically, the theory of special relativity is given by the formula;

E = mc^{2}

Where;

  • E is the energy possessed by a substance.
  • m is the mass.
  • c is the speed of light.

Substituting into the formula, we have;

3.6 * 10^{17} = m * 300000000^{2}

3.6 * 10^{17} = m * 9*10^{16}

m = \frac {3.6 * 10^{17}}{9*10^{16}}

Mass, m = 4 kg

8 0
3 years ago
An object moves 20m east in 30s and then returns to its starting point taking an additional 50s. If west is chosen as the positi
USPshnik [31]

Answer:

b) 0.5 m/s

Explanation:

let V be the averare speed of the object.

the average speed is given by:

V = total distance / total time

   = (20+20)/(30+50)

   = 0.5 m/s

Therefore, the average speed of the object is 0.5 m/s.

7 0
4 years ago
Two beams of coherent light travel different paths, arriving at point P. If the maximum destructive interference is to occur at
Nimfa-mama [501]

Answer:

The path difference between the two waves should be one-half of a wavelength

Explanation:

When two beams of coherent light travel different paths, arriving at point P. If the maximum destructive interference is to occur at point P , then the condition for it is that the path difference of two beams must be odd multiple of half wavelength. Symbolically

path difference = ( 2n+1 ) λ / 2

So path difference may be λ/2 , 3λ/ 2,  5λ/ 2 etc .

Hence right option is

The path difference between the two waves should be one-half of a wavelength.

5 0
3 years ago
The part of the electromagnetic spectrum usually used for communication is
noname [10]
<h2>Answer:</h2>

The part of the electromagnetic spectrum usually used for communication is of  radio waves, infrared waves and microwaves.

But most common waves used in communication are radio waves.

<h3>Explanation:</h3>
  • Radio waves are used to transmit television and radio programmes.
  • While microwaves are used for mobile phones and Wi-Fi.
  • Radio waves are a type of electromagnetic radiation with wavelengths in the electromagnetic spectrum longer than infrared light.
  • Radio waves have frequencies as high as 300 gigahertz (GHz) to as low as 30 hertz (Hz).
5 0
3 years ago
A 1400 kg compact car rear-ends a 2000 kg truck. which vehicle experiences the larger momentum change from the collision?
Fittoniya [83]

Both vehicles experience the same change in momentum.

When the compact car rear ends a truck, they exert equal forces on each other, in accordance with Newton's third law. The force exerted by the car on the truck is equal to the force exerted by the truck on the car.The force acting on the two bodies act for the same interval of time.

According to Newton's second law, the force acting on a body is equal to the rate of change of momentum.

Since the forces are equal,

F=\frac{\Delta p_1}{t} =\frac{\Delta p_2}{t}

therefore, the change in momentum of the car \Delta p_1is equal to the change in the momentum of the truck \Delta p_2.

Thus, both the car and the truck experience the same change in their momentum. However due to the smaller mass of the car, the change in its velocity is greater than the change in the truck's velocity, which has a larger mass.

3 0
3 years ago
Read 2 more answers
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