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Deffense [45]
3 years ago
8

Well i just had a major PTSD attack how is everyone i need to think about something else

Chemistry
2 answers:
Arada [10]3 years ago
6 0

Answer:

Oh so so sorry about that. and thanks for caring for us. anyway we are good wbu

zimovet [89]3 years ago
3 0

Explanation:

im good. i just ate applesauce lol :)

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Electric service has accumulated on an object is referred to as​
lara31 [8.8K]

Answer:

Static Electricity! :)

Explanation:

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3 years ago
Create an outline to organize your presentation. Write the outline for your presentation in the space provided. You can organize
Alex Ar [27]

Answer:

explain on which topic we have to write and organize an essay ?

Explanation:

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3 years ago
A sample of a substance that has a density of 0.824 g/mL has a mass of 0.451g. Calculate the volume of the sample.
Allushta [10]
Density can be calculated using the following rule:
density=mass/volume
therefore,
volume=mass/density

we have mass=0.451g and density=0.824g/ml
substituting in the above equation, we can calculate the volume as follows:
volume = 0.451/0.824 = 0.547 ml
8 0
4 years ago
Copper(II) sulfide is oxidized b molecular oxygen to produce gaseous sulfur trioxide and solid copper (II) oxide. The gaseous pr
Tasya [4]

Explanation:

Copper(II) sulfide reacts with oxygen gas to give solid copper(II) oxide and sulfur trioxide gas.

The reaction is given as:

CuS+2O_2\rightarrow CuO(s)+SO_3(g)

When 1 mol copper(II) sulfide react with 2 moles of oxygen gas it gives 1 mol of solid copper(II) oxide and 1 mol of sulfur trioxide gas

The gas formed in above reaction that is sulfur trioxide reacts with water to give sulfuric acid or hydrogen sulfate.

The reaction is given as:

SO_3(g)+H_2O(l)\rightarrow H_2SO_4(aq)

1 mol of sulfur trioxide gas reacts with 1 mol of liquid water to produce 1 molo of liquid hydrogen sulfate or sulfuric acid

3 0
3 years ago
Can anybody check my answer?
anzhelika [568]

Answer:

\boxed{\text{25. 20 L; 26. 49 K}}

Explanation:

25. Boyle's Law

The temperature and amount of gas are constant, so we can use Boyle’s Law.

p_{1}V_{1} = p_{2}V_{2}

Data:

\begin{array}{rcrrcl}p_{1}& =& \text{100 kPa}\qquad & V_{1} &= & \text{10.00 L} \\p_{2}& =& \text{50 kPa}\qquad & V_{2} &= & ?\\\end{array}

Calculations:

\begin{array}{rcl}100 \times 10.00 & =& 50V_{2}\\1000 & = & 50V_{2}\\V_{2} & = &\textbf{20 L}\\\end{array}\\\text{The new volume will be } \boxed{\textbf{20 L}}

26. Ideal Gas Law

We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.

pV = nRT

Data:  

p = 101.3 kPa

V = 20 L

n = 5 mol

R = 8.314 kPa·L·K⁻¹mol⁻¹

Calculation:

101.3 × 20 = 5 ×  8.314 × T

2026 = 41.57T

T = \dfrac{2026}{41.57} = \textbf{49 K}\\\\\text{The Kelvin temperature is }\boxed{\textbf{49 K}}

6 0
3 years ago
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