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Natasha2012 [34]
2 years ago
15

if 31.2 grams of tin (IV) carbonate are actually formed when this reaction goes to completion, what is the percent yield?

Chemistry
1 answer:
Y_Kistochka [10]2 years ago
6 0

Answer:

I would help but I barely passed my Chem class

Explanation:

It was useless and did not care about it.

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3. Determine the moles of sodium, Na, containing 7.9x1024 atoms.​
-BARSIC- [3]

Answer:

12.7mol Na.

Explanation:

Hello there!

In this case, according to the concept of mole, which stands for the amount of substance, we can recall the concept of Avogadro's number whereby we understand that one mole of any substance contains 6.022x10²³ particles, for the given atoms of sodium, we can calculate the moles as shown below:

7.9x10^{23}atoms*\frac{1mol}{6.022x10^{23}atoms} \\\\

Thus, by performing the division we obtain:

12.7molNa

Regards!

8 0
3 years ago
Does mint actually cool things down
PtichkaEL [24]
The cooling of a mint is just a sensation if you were to put mints into warm water the water would remain warm because it is just a cooling sensation. I hope this helps:)
3 0
3 years ago
5. What is the systemic name for the following structure?
topjm [15]

Answer:

You are not showing the question, but I believe the answer is cis-3,4-dimethyl-3-hexene.

Explanation:

since the substituents are on same side, it call cis. Followed by the name.

5 0
2 years ago
Hellpppppoppopppppppp
Kipish [7]

Answer:

C

Explanation:

it's always colder at night and close to night especially near water and that's when wind tends to blow the most

8 0
3 years ago
Read 2 more answers
How many grams of oxygen are there in 45.7 grams of Ba(NO2),?
Flauer [41]
I’m assuming you mean barium nitrite, Ba(NO2)2.

First convert grams of Ba(NO2)2 to moles using the molar mass of Ba(NO2)2. Then use the mole ratio of 4 moles of oxygen per 1 mole of Ba(NO2)2 to convert to moles of oxygen. Then use the molar mass of oxygen to convert to grams of oxygen.

45.7 g Ba(NO2)2 • 1 mol Ba(NO2)2 / 229.35 g Ba(NO2)2 • 4 mol O / 1 mol Ba(NO2)2 • 16.0 g O / 1 mol O = 12.8 g oxygen
4 0
2 years ago
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