How many molecules of carbon monoxide (co) are needed to react with excess iron (iii) oxide (fe2o3) to produce 11.6 g of iron (f

Question

Dominik [7]

3 years ago

10

How many molecules of carbon monoxide (co) are needed to react with excess iron (iii) oxide (fe2o3) to produce 11.6 g of iron (f

e)?

Chemistry

1 answer:

Troyanec [42] · Answer 1 · 2022-02-01T09:09:43+03:00

<span>8.73 grams CO
The balanced equation for the reaction is
3CO + Fe2O3 ==> 2Fe + 3CO2
So for every 2 atoms of Fe produced, 3 molecules of CO is needed. So let's start by looking up the atomic weights of the involved elements:
Atomic weight iron = 55.845
Atomic weight carbon = 12.0107
Atomic weight oxygen = 15.999
Molar mass CO = 12.0107 + 15.999 = 28.0097 g/mol
Moles iron = 11.6 g / 55.845 g/mol = 0.20771779 mol
Moles CO needed = 0.20771779 mol / 2 * 3 = 0.311576685 mol
Mass CO needed = 0.311576685 mol * 28.0097 g/mol = 8.727169487 g Rounding to 3 significant figures gives 8.73 grams CO</span>