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Anna007 [38]
3 years ago
6

How are volcanoes formed at subduction zones

Physics
2 answers:
nadya68 [22]3 years ago
7 0

Answer:

magma forming above a plate and slowly rising  into the crust  forming a  volcano

Explanation:

hope this helps

gavmur [86]3 years ago
3 0

Answer:

magma forming above a subducting plate slowly rise into the overriding crust causing the formation of a volcano

Explanation:

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Mass ,gravity and height
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What is the force on a 250 kg elevator that is falling freely at 9.8 m/sec2?​
Viefleur [7K]

Answer:

Since it is falling freely, the only force on it is its weight, w.

w = m × g = 250 kg × 9.8 m/s^2 = 2450 Newton/N

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A particle with charge q = 10-9 C and mass m = 5.0 x 10-9 kg is moving in a magnetic field whose magnitude is 0.003 T. The speed
Marina86 [1]

Answer:

a=0.212 m/s²

Explanation:

Given that

q= 10⁻⁹ C

m = 5 x 10⁻⁹ kg

Magnetic filed ,B= 0.003 T

Speed ,V= 500 m/s

θ= 45°

Lets take acceleration of the mass is a m/s²

The force on the charge due to magnetic filed B

F= q V B sinθ

Also F= m a  ( from Newton's law)

By balancing these above two forces

m a= q V B sinθ

a=\dfrac{qVB\ sin\theta}{m}

a=\dfrac{10^{-9}\times 500\times 0.003\times\ sin45^{\circ}}{5\times 10^{-9}}\ m/s^2

a=\dfrac{10^{-9}\times 500\times 0.003\times\dfrac{1}{\sqrt2}}{5\times 10^{-9}}\ m/s^2

a=0.212 m/s²

4 0
3 years ago
Juan's mother drives 12.5 miles southwest to her favorite shopping mall. What is the velocity of her
SVETLANKA909090 [29]

Answer:

Calculate using the formula

Explanation:

velocity= displacement (m)/time(s)

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1km=1000m

7 0
3 years ago
2. A particular planet has a moment of inertia of 9.74 × 1037 kg•m2 and a mass of 5.98 × 1024 kg. Based on these values, what is
mash [69]

Answer:

6.38\cdot 10^6 m

Explanation:

The planet can be thought as a solid sphere rotating around its axis. The moment of inertia of a solid sphere rotating arount the axis is

I=\frac{2}{5}MR^2

where

M is the mass

R is the radius

For the planet in the problem, we have

M=5.98\cdot 10^{24} kg

I=9.74\cdot 10^{37} kg\cdot m^2

Solving the equation for R, we find the radius of the planet:

R=\sqrt{\frac{5I}{2M}}=\sqrt{\frac{5(9.74\cdot 10^{37}}{2(5.98\cdot 10^{24}}}=6.38\cdot 10^6 m

3 0
3 years ago
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