Answer:
3.125 m
Explanation:
We are given that
Mass of box=m=11.2 kg
Speed of box=u=3.5m/s
Coefficient of kinetic friction=
Final velocity,v=0
a.We have to find the horizontal force applied by worker to maintain the motion.
According to question
Horizontal force=F=

Substitute the values
Horizontal force=
b.According to work-energy theorem






Hence, the box slide before coming to rest=3.125 m
Answer:
you don't have to its your choice whether you want to or not.
Explanation:
but you can not leave the fact that there dieing
The answer is <span>C. 49 m/s
The kinetic equation is:
v2 = v1 + a * t
v1 - initial velocity
v2 - final velocity
a - gravitational acceleration
t - time
We know:
v2 = ?
v1 = 0 (in free fall
a = 9.8 m/s
t = 5
</span>v2 = v1 + a * t
v2 = 0 + 9.8 * 5
v2 = 0 + 49
v2 = 49 m/s
1. 2504.63 J
2. 929.5m/s
Hope this helps :)
I can explain it as well if you’d like
ANSWER - (1) are constantly moving (2) have volume (3) have intermolecular forces (4) undergo perfectly elastic collisions (5) have an average kinetic energy proportional to the ideal gas’s absolute temperature