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3 years ago

How are volcanoes formed at subduction zones

Physics

2 answers:

nadya68 [22]3 years ago

7 0

Answer:

magma forming above a plate and slowly rising into the crust forming a volcano

Explanation:

hope this helps

gavmur [86]3 years ago

3 0

Answer:

magma forming above a subducting plate slowly rise into the overriding crust causing the formation of a volcano

Explanation:

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What factors affect potential energy

jok3333 [9.3K]

Mass ,gravity and height

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3 years ago

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What is the force on a 250 kg elevator that is falling freely at 9.8 m/sec2?

Viefleur [7K]

Answer:

Since it is falling freely, the only force on it is its weight, w.

w = m × g = 250 kg × 9.8 m/s^2 = 2450 Newton/N

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3 years ago

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A particle with charge q = 10-9 C and mass m = 5.0 x 10-9 kg is moving in a magnetic field whose magnitude is 0.003 T. The speed

Marina86 [1]

Answer:

a=0.212 m/s²

Explanation:

Given that

q= 10⁻⁹ C

m = 5 x 10⁻⁹ kg

Magnetic filed ,B= 0.003 T

Speed ,V= 500 m/s

θ= 45°

Lets take acceleration of the mass is a m/s²

The force on the charge due to magnetic filed B

F= q V B sinθ

Also F= m a ( from Newton's law)

By balancing these above two forces

m a= q V B sinθ

$a=\dfrac{qVB\ sin\theta}{m}$

$a=\dfrac{10^{-9}\times 500\times 0.003\times\ sin45^{\circ}}{5\times 10^{-9}}\ m/s^2$

$a=\dfrac{10^{-9}\times 500\times 0.003\times\dfrac{1}{\sqrt2}}{5\times 10^{-9}}\ m/s^2$

a=0.212 m/s²

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3 years ago

Juan's mother drives 12.5 miles southwest to her favorite shopping mall. What is the velocity of her

SVETLANKA909090 [29]

Answer:

Calculate using the formula

Explanation:

velocity= displacement (m)/time(s)

1 mile =1.6km

1km=1000m

7 0

3 years ago

2. A particular planet has a moment of inertia of 9.74 × 1037 kg•m2 and a mass of 5.98 × 1024 kg. Based on these values, what is

mash [69]

Answer:

$6.38\cdot 10^6 m$

Explanation:

The planet can be thought as a solid sphere rotating around its axis. The moment of inertia of a solid sphere rotating arount the axis is

$I=\frac{2}{5}MR^2$

where

M is the mass

R is the radius

For the planet in the problem, we have

$M=5.98\cdot 10^{24} kg$

$I=9.74\cdot 10^{37} kg\cdot m^2$

Solving the equation for R, we find the radius of the planet:

$R=\sqrt{\frac{5I}{2M}}=\sqrt{\frac{5(9.74\cdot 10^{37}}{2(5.98\cdot 10^{24}}}=6.38\cdot 10^6 m$

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3 years ago