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Kaylis [27]
3 years ago
9

Which is the best procedure to make a permanent magnet?

Physics
2 answers:
notka56 [123]3 years ago
7 0

placing a magnetically hard material in a strong magnetic field

fgiga [73]3 years ago
3 0
<h3><u>Answer;</u></h3>

<em>Placing a magnetically hard material in a strong magnetic field</em>

<h3><u>Explanation</u>;</h3>
  • <em><u>Magnets</u></em> are those materials that generate magnetic field. Materials may either be <em><u>magnetic materials or non-magnetic materials</u></em>. <em><u>Non magnetic materials</u></em> are those materials that can not be attracted by a magnet while <em><u>magnetic materials</u></em> are those that can be attracted by a magnet.
  • <em><u>Magnetic materials</u></em> may be classified as either soft magnetic materials or hard magnetic materials based on the ease of magnetization. <em><u>Soft magnetic materials </u></em>are those materials that are easily magnetized and easily demagnetized while <em><u>hard magnetic materials </u></em>are hard to magnetize and demagnetized.
  • <em><u>Hard magnetic materials</u></em> are used to make permanent magnets. This is done by placing them in a strong magnetic field.
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3 years ago
You have two square metal plates with side lengths of (6.50 C) cm. You want to make a parallel-plate capacitor that will hold a
gtnhenbr [62]

Answer:

The necessary separation between  the two parallel plates is 0.104 mm

Explanation:

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length of each side of the square plate, L = 6.5 cm = 0.065 m

charge on each plate, Q = 12.5 nC

potential difference across the plates, V = 34.8 V

Potential difference across parallel plates is given as;

V = \frac{Qd}{L^2 \epsilon_o} \\\\d = \frac{V L^2 \epsilon_o}{Q}

Where;

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d = \frac{VL^2 \epsilon_o}{Q} \\\\d =  \frac{34.8*(0.065)^2 *8.854*10^{-12}}{12.5*10^{-9}} \\\\d = 0.000104 \ m\\\\d = 0.104 \ mm

Therefore, the necessary separation between  the two parallel plates is 0.104 mm

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