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Kaylis [27]
3 years ago
9

Which is the best procedure to make a permanent magnet?

Physics
2 answers:
notka56 [123]3 years ago
7 0

placing a magnetically hard material in a strong magnetic field

fgiga [73]3 years ago
3 0
<h3><u>Answer;</u></h3>

<em>Placing a magnetically hard material in a strong magnetic field</em>

<h3><u>Explanation</u>;</h3>
  • <em><u>Magnets</u></em> are those materials that generate magnetic field. Materials may either be <em><u>magnetic materials or non-magnetic materials</u></em>. <em><u>Non magnetic materials</u></em> are those materials that can not be attracted by a magnet while <em><u>magnetic materials</u></em> are those that can be attracted by a magnet.
  • <em><u>Magnetic materials</u></em> may be classified as either soft magnetic materials or hard magnetic materials based on the ease of magnetization. <em><u>Soft magnetic materials </u></em>are those materials that are easily magnetized and easily demagnetized while <em><u>hard magnetic materials </u></em>are hard to magnetize and demagnetized.
  • <em><u>Hard magnetic materials</u></em> are used to make permanent magnets. This is done by placing them in a strong magnetic field.
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3 years ago
The speed of a certain electron is 995 km s−1 . If the uncertainty in its momentum is to be reduced to 0.0010 per cent, what unc
Tpy6a [65]

Answer:

The uncertainty in the location that must be tolerated is 1.163 * 10^{-5} m

Explanation:

From the uncertainty Principle,

Δ_{y} Δ_{p} = \frac{h}{2\pi }

The momentum P_{y} = (mass of electron)(speed of electron)

                                = (9.109 * 10^{-31}kg)(995 * 10^{3} m/s)

                                = 9.0638 * 10^{-25}kgm/s

If the uncertainty is reduced to a 0.0010%, then momentum

                              = 9.068 * 10^{-30}kgm/s

Thus the uncertainty in the position would be:

                              Δ_{y} = \frac{h}{2\pi } * \frac{1}{9.068 * 10^{-30} }

                              Δ_{y} \geq  1.163 * 10^{-5}m

5 0
3 years ago
A 2.2 kg model rocket is shot straight up in the air from the ground, with an initial velocity of 36.4 m/s. The rocket reaches i
alexandr1967 [171]

Answer:

Explanation:

Ignoring friction, the initial kinetic energy will convert to maximum potential energy at its highest point.

PE = KE

mgh = ½mv²

    h = v²/2g

    h = 36.4²/ (2(9.81))

    h = 67.53109...

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3 0
2 years ago
A boy threw a ball upward and it took 3 sec to reach the highest point. Determine the initial velocity of the ball.
makkiz [27]

Answer:

V initial = 29.4 m.s²

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( Using the laws of motion)

V final = V initial + Acceleration × time

0 = V initial + ( -9.8)(3)

29.4 = V initial

* I took upward as positive that's why I substituted -9.8 *

* for V final we know that at maximum height the ball is not moving thats why is = 0 *

6 0
1 year ago
The velocity of a car doubles over a short period of time. Which additional information is sufficient to determine the amount of
Rom4ik [11]

Answer:

Time and velocity

Explanation:

The time taken for the velocity to double is very important to find the amount of acceleration the car acquires.

Acceleration is the rate of change of velocity with time.

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v is the initial velocity

u is the final velocity

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 So, the velocity and time is needed to calculate the value of the acceleration the car undergoes.

4 0
3 years ago
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