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Kaylis [27]
3 years ago
9

Which is the best procedure to make a permanent magnet?

Physics
2 answers:
notka56 [123]3 years ago
7 0

placing a magnetically hard material in a strong magnetic field

fgiga [73]3 years ago
3 0
<h3><u>Answer;</u></h3>

<em>Placing a magnetically hard material in a strong magnetic field</em>

<h3><u>Explanation</u>;</h3>
  • <em><u>Magnets</u></em> are those materials that generate magnetic field. Materials may either be <em><u>magnetic materials or non-magnetic materials</u></em>. <em><u>Non magnetic materials</u></em> are those materials that can not be attracted by a magnet while <em><u>magnetic materials</u></em> are those that can be attracted by a magnet.
  • <em><u>Magnetic materials</u></em> may be classified as either soft magnetic materials or hard magnetic materials based on the ease of magnetization. <em><u>Soft magnetic materials </u></em>are those materials that are easily magnetized and easily demagnetized while <em><u>hard magnetic materials </u></em>are hard to magnetize and demagnetized.
  • <em><u>Hard magnetic materials</u></em> are used to make permanent magnets. This is done by placing them in a strong magnetic field.
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Along a horizontal snow-covered track, a sled, of mass m = 105 kg, slides by the action of a horizontal force of 230 N. The coef
Andrew [12]

Answer:

Explanation:

The only thing I can figure you need here is the accleration of the sled. The equation we need to find this is Newton's Second Law that says that sum of the forces acting on an object is equal to the object's mass times its acceleration. For us, that looks like this because of the friction working against the sled:

F - f = ma but of course it's much more involved than that simple equation! We have the F value as 230 N, and we have the mass as 105, but we do not have the frictional force, f, and we need it to solve for a in the above equation. We know that

f = μF_n where μ is the coefficient of friction, and F_n is the normal force, aka weight of the object. We will use the coefficient of friction and find the weight in order to fill in for f:

F_n=mg so

F_n=(105)(9.8) so the weight of the sled is

F_n= 1.0 × 10³ with the correct number of sig dig there. Now to find f:

f = (.025)(1.0 × 10³) so

f = 25 to the correct number of sig fig. Now on to our "real" equation:

F - f = ma and

230 - 25 = 105a. We have to do the subtraction first, round, and then divide since the rules for addition and subtraction are different from the rules for dividing and multiplying.

230 - 25 will round to the tens place giving us 210. Then

210 = 105a. 210 has 2 sig figs in it while 105 has 3, so we will divide and round to 2 sig fig:

a = 2.0 m/sec²

3 0
2 years ago
Does a generator start a Direct Current?
lesya [120]
A direct-current (DC) generator is a rotating machine that supplies an electrical output with unidirectional voltage and current. ... The field is produced by direct current in field coils or by permanent magnets on the stator. The output, or armature, windings are placed in slots in the cylindrical iron rotor.
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2 years ago
It takes a minimum distance of 57.46 m to stop a car moving at 13.0 m/s by applying the brakes (without locking the wheels). Ass
vivado [14]

Answer:

The minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

Explanation:

We know by equation of motion that,

v^{2}=u^{2}+2\cdot a \cdot s

Where, v= final velocity m/sec

u=initial velocity m/sec

a=Acceleration m/Sec^{2}

s= Distance traveled before stop m

Case 1

u=  13 m/sec, v=0, s= 57.46 m, a=?

0^{2} = 13^{2}  + 2 \cdot a \cdot57.46

a = -1.47 m/Sec^{2} (a is negative since final velocity is less then initial velocity)

Case 2

u=29 m/sec, v=0, s= ?, a=-1.47 m/Sec^{2} (since same friction force is applied)

v^{2} = 29^{2}  - 2 \cdot 1.47 \cdot S

s = 285.94 m

Hence the minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

4 0
2 years ago
What is the mechanical advantage of a pulley?
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What are the 3 main states of matter in water?/
BigorU [14]

Answer:

ice (solid), water (liquid) and vapor (gas)

Explanation:

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2 years ago
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