Question

A crate having mass 50.0 kg falls horizontally off the back of the flatbed truck, which is traveling at 100 km/h. Find the value of the coefficient of kinetic friction between the road and crate if the crate slides 50 m on the road in coming to rest. The initial speed of the crate is the same as the truck, 100 km/h.

Answer 1

Answer:

$\mu = 0.786$

Explanation:

As we know that initial speed of the crate is

$v_i = 100 km/h$

$v_i = 27.78 m/s$

now finally the crate will come to rest

so we have

$v_f = 0$

now the deceleration due to frictional force is given as

$a = -\mu g$

distance moved by the crate before it will stop is given as

$d = 50 m$

so we will have

$0 - 27.78^2 = 2(-\mu(9.81))50$

$\mu = 0.786$