Answer:
No. of electrons of the element
Answer:
Q = 25.6 j
Explanation:
Given data:
Energy needed= ?
Mass of lead = 10.0 g
Initial temperature = 30 °C
Final temperature = 50°C
Cp = 0.128 j/g.°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 50°C - 30°C
ΔT = 20°C
Now we will put the values in formula.
Q = 10 g × 0.128 j/g.°C × 20°C
Q = 25.6 j
Isotopes are the atoms of the same element with same atomic number but different mass number isotopes of same element have same chemical properties due to same number of electrons atomic number of an atom is the number of electrons protons in it and mass number is the sum of protons
He discovered and named the atomic nucleus, the proton, the alpha particle, and the beta particle.
Answer:
V₂ = 2.0 Liters at STP conditions
Explanation:
Solving problem using the combined gas law
Given:
Case I Conditions Cast II Conditions
P₁ = 825mmHg P₂ = 760mm
V₁ = 2.30 Liters V₂ = ?
T₁ = 70°C + 273 = 343K T₂ = 0°C = 273K
Substitute into combined gas law assuming moles of gas remains constant; solve for unknown volume under case 2 conditions
P₁·V₁/n₁·T₁ = P₂·V₂/n₂T₂ => V₂ = P₁·V₁·T₂ / P₂·T₁ => note: in this solution, moles of gas remains constant as is disregarded in final calculation.
V₂ = (825mm)(2.3L)(273K) / (760mm)(343K) = 1.987 Liters (calculator answer) ≅ 1.9 Liters (2 sig figs based on given volume (V₁)
V₂ = 1.987 Liters ≅ 2.0 Liters (2 sig figs based on given volume (V₁)
