Calculate the molar mass for calcium phosphite.

When sodium is excited in a flame, two ultraviolet spectral lines at lambda - 372.1 nm and lambda = 376.4 nm respectively are em

suter [353]

The wavelength that represented photons is at <span>lambda = 376.4 nm.
The wavelength with the higher energy is at </span><span>lambda - 372.1 nm.
The longer wavelength is, of course, </span> at lambda 376.4 <span>nm.
The wavelength with the higher frequency is </span> 376.4 <span>nm.</span><span>
</span><span>
</span>

3 0

3 years ago

Read 2 more answers

Need help !!!!! ASAP

Korolek [52]

<h2>Hello!</h2>

The answer is:

The new volume is 2.84 L.

$V_{2}=2.84L$

To solve the problem, we need to remember what STP means. STP means that the gas is at standard temperature and pressure, or 273.15 K (0°C) and 1 atm.

Also, we need to use the Combined Gas Law, since the temperature, the pressure and the volume are being changed.

The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using , Gay-Lussac's Law, Charles's Law, and Boyle's Law.

The law is defined by the following equation:

$\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}$

Where,

$P_{1}$ is the first pressure.

$V_{1}$ is the first volume.

$T_{1}$ is the first temperature.

$P_{2}$ is the second pressure.

$V_{2}$ is the second volume.

$T_{2}$ is the second temperature.

So, we are given the following information:

$V_{1}=2L\\P_{1}=1atm\\T_{1}=0\°C=273.15K\\P_{2}=80kPa=0.8atm\\T_{2}=37\°C=37+273=310K$

Then, isolating the new volume, and substituting, we have:

$\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}\\\\V_{2}=\frac{P_{1}V{1}}{T_{1}}*\frac{T_{2}}{P_{2}}\\\\V_{2}=\frac{1atm*2L}{273.15K}*\frac{310K}{0.8kPa}=2.84L$

Hence, the new volume is 2.84 L.

$V_{2}=2.84L$

Have a nice day!

4 0

4 years ago

Explain what "LEO the lion goes GER" means based upon what you have learned

olchik [2.2K]

"LEO the lion goes GER" means based upon the oxidation and reduction reactions.

<h3>What is oxidation and reduction reaction?</h3>

Oxidation reactions are those reactions in which lossing of electrons are taking place from the substrate molecule and in reduction process gaining of electrons is done by substrate molecules.

The phrase "LEO the lion goes GER" is used in the context of oxidation and reduction reactions. Meaning of the terms:
LEO → Lose electrons = oxidation

GER → Gain electrons = reduction

Hence the given line is based on oxidation and reduction.

To know more about oxidation and reduction, visit the below link:
brainly.com/question/4222605

#SPJ1

3 0

2 years ago

Identify the standard metal cations in the active components of soaps

rjkz [21]

Answer is: standard metal cations are sodium cation (Na⁺), potassium cation (K⁺), magnesium cation (Mg²⁺) and calcium cation (Ca²⁺).
Soap<span> is a </span>salt<span> of a </span>fatty acid. When soap have sodium and potassim cations, that is toilet soap and when soap have magnesium and calcium cations, that soap is called <span>metallic soap.</span>

8 0

4 years ago

What amount of acid is esterified if a mixture consist initially of 1.0mole of ethanoic acid,1.0mole of ethanol and 1.0mole of w

ale4655 [162]

Answer:

0.54 mole

Explanation:

CH3COOH CH3CH2OH CH3COOCH2CH3 H2O

Initial concentration 1.0 mole 1.0 mole 0 mole 1.0mol

Change - x - x + x + x

Equilibrium (1.0 - x) (1.0 - x) x (1.0 + x)

K = [CH3COOCH2CH3]*[H2O]/[CH3COOH]*[CH3CH2OH]

x*(1.0+x)/(1.0-x)(1.0-x) = 4.0

x+x²=4*(1-x)²

x+x² = 4(1² - 2x + x²)

x + x² = 4 - 8x + 4x²

4 - 8x + 4x²- x² - x= 0

3x² - 9x + 4 = 0

x=2.5 , x=0.54

2.5 mole of acid cannot be esterified, because there is only 1.0 mole of acid,

so answer is 0.54 mole.

3 0

4 years ago