Three ways (out of the many) are:
Change of temperature
Color change
Formation of gas
Hope this helps!! (:
Answer:
the first one is branched, the second one is also branched and the third one is cycloalkane
Answer:
a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.
Explanation:
The heating curve is a curve that represents temperature (T) in the y-axis vs. added heat (Q) in the x-axis. The slope is T/Q = 1/C, where C is the heat capacity. Then, the higher the slope, the lower the heat capacity. For a constant mass, it can also represent the specific heat capacity (c).
Heats of vaporization and fusion cannot be calculated from these sections of the heating curve.
<em>Which statement below explains that?</em>
<em>a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.</em> YES.
<em>b. The specific heat capacity of the gaseous ethanol is greater than the specific heat capacity of liquid ethanol.</em> NO.
<em>c. The heat of vaporization of ethanol is less than the heat of fusion of ethanol.</em> NO.
<em>d. The heat of vaporization of ethanol is greater than the heat of fusion of ethanol.</em> NO.
Molar mass KBr = 119 g/mol
Volume in liters: 250.0mL / 1000 => 0.25 L
n = M x V
n = 1.20 x 0,25 => 0.3 moles of KBr
Therefore:
1 mole KBr ----------- 119 g
0.3 moles KBr -------- ??
0.3 x 119 / 1 => 35.7 g of KBr
Conc = moles / Vol you have C but need to find moles
moles KCl = mass / molar mass
25 g / 74.55 g,p;
0.335 moles
So rearrange the formula to find volume. Vol = moles / Conc
0.335 moles / 0.750 mol / L = 0.447 L or 447 mL
The answer in this question is 447 mL.
