To calculate the number of electrons from spherical conductor first we use the formula,
![V= k\frac{q}{r}](https://tex.z-dn.net/?f=V%3D%20k%5Cfrac%7Bq%7D%7Br%7D)
Here, k is a constant with a value of
, q is the charge and r is the radius and its value of 0.200 m.
Substituting these value in above formula, we get
![5.50 kV =\frac{8.99 \times 10^9 N.m^{2} /C^2\times q}{0.200 m}](https://tex.z-dn.net/?f=5.50%20kV%20%3D%5Cfrac%7B8.99%20%5Ctimes%2010%5E9%20N.m%5E%7B2%7D%20%2FC%5E2%5Ctimes%20q%7D%7B0.200%20m%7D)
or ![q= \frac{5.50\times10^3 V\times0.200 m}{8.99 \times 10^9 N.m^{2} /C^2}](https://tex.z-dn.net/?f=q%3D%20%5Cfrac%7B5.50%5Ctimes10%5E3%20V%5Ctimes0.200%20m%7D%7B8.99%20%5Ctimes%2010%5E9%20N.m%5E%7B2%7D%20%2FC%5E2%7D)
![q=1.2\times 10^{-7} C](https://tex.z-dn.net/?f=q%3D1.2%5Ctimes%2010%5E%7B-7%7D%20C)
Now number of electron,
![N= \frac{1.2\times 10^{-7} C}{1.6\times 10^{-19}C/e }](https://tex.z-dn.net/?f=N%3D%20%5Cfrac%7B1.2%5Ctimes%2010%5E%7B-7%7D%20C%7D%7B1.6%5Ctimes%2010%5E%7B-19%7DC%2Fe%20%7D)
![N=7.5\times 10^{11} electrons](https://tex.z-dn.net/?f=N%3D7.5%5Ctimes%2010%5E%7B11%7D%20electrons)
Hence, the number of electrons to be removed from conductor would be ![7.5\times 10^{11} electrons](https://tex.z-dn.net/?f=7.5%5Ctimes%2010%5E%7B11%7D%20electrons)
Answer:
trade and agriculture
Explanation:
i got it right on the test
Answer:
R = 0.0015Ω
Explanation:
The formula for calculating the resistivity of a material is expressed as;
ρ = RA/l
R is the resistance
ρ is the resistivity
A is the area of the wire
l is the length of the wire
Given
l = 85cm = 0.85m
A = πr²
A = 3.14*0.0018²
A = 0.0000101736m²
ρ = 1.75 × 10-8Ωm.
Substitute into the formula
1.75 × 10-8 = 0.0000101736R/0.85
1.4875× 10-8 = 0.0000101736R
R = 1.4875× 10-8/0.0000101736
R = 0.0015Ω
Answer:
the positive and negative charges of the hydrogen and oxygen atoms that make up water molecules makes them attracted to each other
Explanation:
Hope this helps dude
Answer:
18 L
Explanation:
Use ideal gas law:
PV = nRT
Find initial number of moles, but first convert to units that match the gas constant units.
(200,000 Pa) (0.025 m³) = n (8.314 Pa m³ / mol / K) (25 + 273.15 K)
n = 2.017 mol
At the new pressure and temperature:
(250,000 Pa) V = (2.017 mol) (8.314 Pa m³ / mol / K) (0 + 273.15 K)
V = 0.018 m³
V = 18 L