The number of mole of ethanol present in the sample is 0.005 mole
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation
Mole = mass / molar mass
With the above formula, we can obtain the mole of ethanol
<h3>How to determine the mole of ethanol</h3>
- Mass of ethanol = 0.2301 g
- Molar mass of ethanol = 46 g/mol
- Mole of ethanol = ?
Mole = mass / molar mass
Mole of ethanol = 0.2301 / 46
Mole of ethanol = 0.005 mole
Complete question
A sample of ethanol (C2H6O) has a mass of 0.2301 g. Complete combustion of this sample causes the temperature of a bomb calorimeter to increase by 1.33°C. The calorimeter has a mass of 2.000 kg and a specific heat of 2.45 J/g•°C. How many moles of ethanol are present in the sample?
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The differing heart rates is the dependent variable. This is because it is dependent on the exercise that will depict the heart rate
cu=1*63g=63g
n=2*14g=28g
o=6*16g=96g
total=187g/mol
122(1 mol/187)(6.02*10^23)= 3.92*10^23
Answer:
66.0 atm
Explanation:
We can calculate the osmotic pressure (π) using the following expression.
where,
Step 1: Calculate i
Sodium sulfate completely dissociates according to the following equation.
Na₂SO₄ ⇒ 2 Na⁺ + SO₄²⁻
Since it produces 3 ions, i = 3.
Step 2: Calculate M
We can calculate the molarity of Na₂SO₄ using the following expression.
Step 3: Calculate T
We will use the following expression.
K = °C + 273.15
K = 20°C + 273.15 = 293 K
Step 4: Calculate π