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malfutka [58]
3 years ago
11

Of the substances xe, ch3cl, hf, which has: (a) the smallest dipole–dipole forces? (b) the largest hydrogen bond forces? (c) the

largest dispersion forces?
Chemistry
2 answers:
frosja888 [35]3 years ago
6 0
A) <span>he smallest dipole–dipole forces have xenon (Xe), because xenon is a noble gas and have stable electron configuration and do not form dipole.
b) t</span><span>he largest hydrogen bond forces have HF because hydrogen bonds are formed between hydrogen and F, O and N.
</span>c) the largest dispersion forces have CH₃Cl because he has strongest <span>induced temporary dipoles.</span>
Pavel [41]3 years ago
6 0

Answer:

(a) Xe

(b) HF

(c) Xe

Explanation:

<u>Dipole-dipole interaction:- </u>

This is the interaction between the two dipoles in the molecule which is formed by varying electronegativities.

<u>Hydrogen bonding:- </u>

Hydrogen bonding is a special type of the dipole-dipole interaction and it occurs between hydrogen atom that is bonded to highly electronegative atom which is either fluorine, oxygen or nitrogen atom.

Partially positive end of the hydrogen atom is attracted to partially negative end of these atoms which is present in another molecule. It is strong force of attraction between the molecules.

<u>London dispersion forces:- </u>

The intermolecular force acting in the molecule are induced dipole-dipole forces or London Dispersion forces / van der Waals forces which are the weakest intermolecular force.

<u>Thus, Xe will have the smallest dipole–dipole forces because there is no chances of forming a dipole. Also, it has the largest dispersion forces as the other both has dipole and involved in other interactions.</u>

<u>Also, H-F bond is more polar than C-Cl bond and thus HF has the largest hydrogen bond forces.</u>

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- Mole fraction of a particular component of interest = (number of moles of the component of interest) ÷ (total number of moles)

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