Answer:
10.01 cm
Explanation:
Given that,
The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece of fat tissue was 0.13 ms.
The average propagation speed for sound in body tissue is 1540 m/s.
We need to find the depth when the reflection occur. We know that, the distance is double when transmitting and arriving. So,
or
d = 10.01 cm
So, the reflection will occur at 10.01 cm.
Answer:
hot I checked already in my phone
Answer:
4611.58 ft/s²
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 32.174 ft/s²
Equation of motion
Magnitude of acceleration while stopping is 4611.58 ft/s²
Answer:
The correct answer is:
False
Explanation:
Nuclear fission is the splitting of nucleus of an atom which results in the emission of high amount of energy.
<u>Example:</u>
Heavy atom (i.e. uranium) when bombarded with neutrons, its nucleus split into smaller lighter weight nuclei and release a huge amount of energy. (Nuclear fission also takes place without neutrons i.e. in the form of radioactive decay (the process in which an unstable nucleus of an atom releases energy in the form of radiation)).
Venis rotates on it's axis more slower than Earth.
