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4 years ago

7

Amy uses 20N of force to push a lawn mower 10 meters. How much work does she do? *

1 answer:

babunello [35]4 years ago

4 0

She does 200J .

We know she uses 20N of force and 10m is the distance. We multiply both numbers and we are given our answer of 200J. Hope this was helpful. :)

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if a person can jump 2m in earth surface how high can he jump in the moon (g of moon = 1.66m/s, g of earth = 9.8 m/s) [hint: use

julia-pushkina [17]

Answer:

$h_{moon} = 11.8\ m$

Explanation:

Since the work done is same everywhere in the universe. Hence, the work done in jumping will be same for the person on moon and earth:

$W_{moon} = W_{earth}\\\\P.E_{moon} = P.E_{earth}\\\\mg_{moon}h_{moon} = mg_{earth}h_{earth}\\\\g_{moon}h_{moon} = g_{earth}h_{earth}\\\\(1.66\ m/s^2)h_{moon} = (9.8\ m/s^2)(2\ m)\\\\h_{moon} = \frac{(9.8\ m/s^2)(2\ m)}{1.66\ m/s^2}\\\\h_{moon} = 11.8\ m$

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3 years ago

19. Use a scale ray diagram to find the image position of

luda_lava [24]

I hope that helps you!!!!!!

7 0

3 years ago

Which of the following statements is not true

mixer [17]

Answer:

The answer is the First One

Explanation:

Electromagnets can work with a magnetic source, and not just electric. sorry if my answer turns out to be wrong

3 0

3 years ago

When and where is the bar graph used?

ira [324]

<span>bar graphs are used to compare things between different groups or to track changes over time</span>

4 0

3 years ago

Read 2 more answers

Two long, parallel wires separated by 2.00 cm carry currents in opposite directions. The current in one wire is 1.75 A, and the

Natasha_Volkova [10]

The force per unit length between the two wires is $6.0\cdot 10^{-5} N/m$

Explanation:

The magnitude of the force per unit length exerted between two current-carrying wires is given by

$\frac{F}{L}=\frac{\mu_0 I_1 I_2}{2\pi r}$

where

$\mu_0 = 4\pi \cdot 10^{-7} Tm/A$ is the vacuum permeability

$I_1, I_2$ are the currents in the two wires

r is the separation between the two wires

For the wires in this problem, we have

$I_1 = 1.75 A$

$I_2 = 3.45 A$

r = 2.00 cm = 0.02 m

Substituting into the equation, we find

$\frac{F}{L}=\frac{(4\pi \cdot 10^{-7})(1.75)(3.45)}{2\pi (0.02)}=6.0\cdot 10^{-5} N/m$

Learn more about current and magnetic fields:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

brainly.com/question/3874443

brainly.com/question/4240735

#LearnwithBrainly

4 0

4 years ago