Answer:
DE = 6 cm
Step-by-step explanation:
Let DE = x cm.
Since DE is parallel to AB therefore by the alternate interior angles theorem, m∠BAD = m∠ADE and m∠ABE = m∠DEB ............(1)
As AD is an angle bisector of ∠A, therefore m∠EAD = m∠DAB ; Since BE is an angle bisector of ∠B ⇒ m∠ABE = m∠EBD.
Therefore, from (1) We get , m∠EAD = m∠ADE and m∠EBD = m∠BED.
So, the triangles ADE and EDB are then isosceles with AE = ED and ED = DB.
So AE = DE = DB = x, and since the perimeter of ABDE is 30 cm, then
12 + x + x + x = 30
⇒ 12 + 3x = 30
⇒ x = 6
Hence, the length of DE is 6 cm.
Answer:
b) -9.25
Step-by-step explanation:
-1/4 = -0.25
-9 + -0.25 = -9.25
-10, -9.75, -9.5, -9.25, -9, -8.75, -8.5, -8.25, -8, -7.75, -7.5, -7.25, -7
Hope this helps!
The entire yard is 36x54 so you would draw a rectangle with those measurements, since there is a border of 3 you should draw another rectangle in the middle with measurements 6 less than the original. 30x48
since you are finding the area of the walk, you would find the larger area, then subtract the smaller rectangle
(36*54)-(30*48)
1944-1440
504 square feet of walk
x is case of almonds and y is case of walnuts.
Almonds are packaged 15 bags per case and walnuts are packaged 17 bags per case.
H-E-B orders no more than 200 bags of almonds and walnuts at a time.
So,
x + y < 200
where x and y refers to the number of bags
=======================================================
H-E-B pays $24 per case of almonds and $27 per case of walnuts, but will not order more than $300 total at any one time.
But keep in mind that : Almonds are packaged 15 bags per case and walnuts are packaged 17 bags per case.
So,
24 * (x/15) + 27 * (y/17) < 300
===========================================================
The constraints are:
x + y < 200
(24/15) x + (27/17) y < 300
So, the graph of the previous constraints is as following :
Answer:
The second option
Step-by-step explanation:
Here, we need to multiply each part of the matrix by -10.
This will give us: [ -230 380 ]
[ -170 60 ]
So, the answer is the second option.
