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anastassius [24]
2 years ago
13

A student is investigating gravity and falling objects. She drops three balls and times how long it takes each ball to hit the g

round. What is the most likely source of error?
(1 point)

She used balls that are different sizes.

She did not measure the circumference of the balls.

She dropped the balls from different heights.

She did not measure the mass after the balls hit the ground.

Physics
2 answers:
Goshia [24]2 years ago
8 0

Answer: c

Explanation:

bc the 26 gram ball should of fell much faster

nignag [31]2 years ago
7 0

Answer:C

Explanation: This is because the time for the 26 gram ball was around 6 seconds longer which if they were dropped at the same height then the ball with more mass would fall faster because of its gravitational pull.

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Heather and Jerry are standing on a bridge 49 mm above a river. Heather throws a rock straight down with a speed of 17 m/sm/s .
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Answer:

3.467 s

Explanation:

given,

distance , d = 49 mm = 0.049 m

initial speed of the of the rock, v = 17 m/s

time taken by the Heather rock to reach water

using equation of motion

s = ut +\dfrac{1}{2}at^2

taking downward as negative

-0.049 = -17 t -\dfrac{1}{2}\times 9.8\times t^2

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now,

t_1 = \dfrac{-(17)\pm \sqrt{17^2 - 4\times 4.9 \times (-0.049)}}{2\times 4.9}

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rejecting negative values

t₁ = 0.0028 s

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using equation of motion

s = ut +\dfrac{1}{2}at^2

taking downward as negative

-0.049 = 17 t -\dfrac{1}{2}\times 9.8\times t^2

4.9 t² - 17 t - 0.049 = 0

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t_2 = \dfrac{-(-17)\pm \sqrt{17^2 - 4\times 4.9 \times (-0.049)}}{2\times 4.9}

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now, time elapsed is = t₂ - t₁ = 3.47 - 0.0028 = 3.467 s

5 0
3 years ago
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