A student is investigating gravity and falling objects. She drops three balls and times how long it takes each ball to hit the g
round. What is the most likely source of error?
(1 point)
She used balls that are different sizes.
She did not measure the circumference of the balls.
She dropped the balls from different heights.
She did not measure the mass after the balls hit the ground.
(1 point)
She used balls that are different sizes.
She did not measure the circumference of the balls.
She dropped the balls from different heights.
She did not measure the mass after the balls hit the ground.
2 answers:
You might be interested in
Answer:
the block reaches higher than the sphere
\frac{y_{sphere}} {y_block} = 5/7
Explanation:
We are going to solve this interesting problem
A) in this case a sphere rolls on the ramp, let's find the speed of the center of mass at the exit of the ramp
Let's use the concept of conservation of energy
starting point. At the top of the ramp
Em₀ = U = m g y₁
final point. At the exit of the ramp
Em_f = K + U = ½ m v² + ½ I w² + m g y₂
notice that we include the translational and rotational energy, we assume that the height of the exit ramp is y₂
energy is conserved
Em₀ = Em_f
m g y₁ = ½ m v² + ½ I w² + m g y₂
angular and linear velocity are related
v = w r
the moment of inertia of a sphere is
I = m r²
we substitute
m g (y₁ - y₂) = ½ m v² + ½ ( m r²) (
)²
m g h = ½ m v² (1 + )
where h is the difference in height between the two sides of the ramp
h = y₂ -y₁
mg h = (
m v²)
v = √5/7 √2gh
This is the exit velocity of the vertical movement of the sphere
v_sphere = 0.845 √2gh
B) is the same case, but for a box without friction
starting point
Em₀ = U = mg y₁
final point
Em_f = K + U = ½ m v² + m g y₂
Em₀ = Em_f
mg y₁ = ½ m v² + m g y₂
m g (y₁ -y₂) = ½ m v²
v = √2gh
this is the speed of the box
v_box = √2gh
to know which body reaches higher in the air we can use the kinematic relations
v² = v₀² - 2 g y
at the highest point v = 0
y = vo₀²/ 2g
for the sphere
y_sphere = 5/7 2gh / 2g
y_esfera = 5/7 h
for the block
y_block = 2gh / 2g
y_block = h
therefore the block reaches higher than the sphere
Answer:
The hummingbird travels the total distance is 10 m
Explanation:
Given that,
A hummingbird flies forward and backward.
According to figure,
We know that,
The total distance is equal to the sum of all distance.
Forward direction is positive and backward direction is negative.
We need to calculate the hummingbird travels the total distance
Using figure,
Put the value into the formula
Hence, The hummingbird travels the total distance is 10 m.
Pressure- Pascal()
Force- Newton
Area-(Square metre)
<u>Explanation:</u>
- Pressure is force continuous force applied to an object. The applied force is always perpendicular to the surface of the object.
- Force is a push or pulls on an object by an external body where it changes its state from rest to motion.
- Force is said to have both magnitude and direction.
- Area is the portion that shows the scale of a 2D form or configuration in the level. The covering area is its analog on the 2D surface of a 3D object.