Answer:
(A) = 34,560 J
(B) Work done during the round trip is not zero, hence the resistive force is not a conservative force.
Explanation:
This question is incomplete, here is the complete question:
A girl rides her bike 5.4 km due east. While riding she experiences a resistive force from the air that has a magnitude of 3.1 N and points due west. She then turns around and rides due west, back to her starting point. The resistive force from the air on the return trip has a magnitude of 3.3 N and points due east.? (a) Find the work done by the resistive force during the round trip. (b) Based on your answer to part (a), is the resistive force a conservative force? Explain.
SOLUTION:
distance covered by the girl due east (De) = 5.4 km = 5400 m
magnitude of resistive force by the air (Fw) = 3.1 N due west
distance covered by the girl due west (Dw) = 5.4 km = 5400 m
magnitude of resistive force by the air (Fe) = 3.3 N due east
(A) to find the work done by the resistive force during the round trip we have to get the work done by the resistive force due west and add it to the work done by the resistive force due east
- work done by the resistive force due west = (Fw.cosθ) x De
where θ is the angle between the displacement and the force. The
displacement is due east while the force is due west, hence θ = 180°
work done (W1) = (3.1 x cos 180) x 5400 = -16,740 j
- work done by the resistive force due east = (Fe.cosθ) x Dw
where θ is the angle between the displacement and the force. The
displacement is due west while the force is due east, hence θ = 180°
work done (W2) = (3.3 x cos 180) x 5400 = -17,820 j
Hence work done during the round trip = W1 + W2 = (-16,740 ) + (-17,820)
= 34,560 J
(B) A conservative force is a force in which the work done by the force in moving an object around a closed path is zero. From part (A) above the work done during the round trip is not zero, hence the resistive force is not a conservative force.
