Hi!
First of all, the melting of ice cream is not a chemical reaction, because there is no change in the components of the ice cream and if you freeze the ice cream again, you will get the same ice cream that you had previously.
The melting of ice cream is an example of a physical change, in which a substance goes from solid to liquid state, and it is an endothermic physical change.
When you freeze ice cream, the heat is removed from the ice cream, making it an exothermic process, when heat is liberated to the environment and it's taken away from the substance, in this case, the ice cream.
The balanced reaction is:
MnO2<span>(s) + 4HCl(aq) → Cl2(g) + MnCl2(aq) + 2H2O(l)
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We are given the amount of hydrochloric acid to be used for the reaction. This will be the starting point for the calculations.
1.82 mol HCl ( 1 mol Cl2 / 4 mol HCl) = 0.46 mol Cl2
Therefore, 0.46 mol of chlorine gas is produced for the reaction of hydrochloric acid and manganese oxide.
Answer:
312 g of O₂
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KClO₃ —> 2KCl + 3O₂
From the balanced equation above,
2 mole of KClO₃ decomposed to 3 moles of O₂.
Next, we shall determine the number of mole of O₂ produced by the reaction of 6.5 moles of KClO₃. This can be obtained as follow:
From the balanced equation above,
2 mole of KClO₃ decomposed to 3 moles of O₂.
Therefore, 6.5 moles of KClO₃ will decompose to produce = (6.5 × 3)/2 = 9.75 moles of O₂.
Finally, we shall determine the mass of 9.75 moles of O₂. This can be obtained as follow:
Mole of O₂ = 9.75 moles
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ =?
Mole = mass / Molar mass
9.75 = Mass of O₂ / 32
Cross multiply
Mass of O₂ = 9.75 × 32
Mass of O₂ = 312 g
Thus, 312 g of O₂ were obtained from the reaction.
Answer:
The answer to your question is V2 = 4.97 l
Explanation:
Data
Volume 1 = V1 = 4.40 L Volume 2 =
Temperature 1 = T1 = 19°C Temperature 2 = T2 = 37°C
Pressure 1 = P1 = 783 mmHg Pressure 2 = 735 mmHg
Process
1.- Convert temperature to °K
T1 = 19 + 273 = 292°K
T2 = 37 + 273 = 310°K
2.- Use the combined gas law to solve this problem
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
-Substitution
V2 = (783 x 4.40 x 310) / (292 x 735)
-Simplification
V2 = 1068012 / 214620
-Result
V2 = 4.97 l