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Schach [20]
3 years ago
6

What volume is occupied by 0.109 molmol of helium gas at a pressure of 0.98 atmatm and a temperature of 307 K

Chemistry
1 answer:
KATRIN_1 [288]3 years ago
6 0

Answer:

2.8 L

Explanation:

From the question given above, the following data were obtained:

Number of mole (n) = 0.109 mole

Pressure (P) = 0.98 atm

Temperature (T) = 307 K

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

The volume of the helium gas can be obtained by using the ideal gas equation as follow:

PV = nRT

0.98 × V = 0.109 × 0.0821 × 307

0.98 × V = 2.7473123

Divide both side by 0.98

V = 2.7473123 / 0.98

V = 2.8 L

Thus, the volume of the helium gas is 2.8 L.

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Nimfa-mama [501]

Answer: 0.87 g of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel.

Explanation:

According to the dilution law,

C_1w_1+C_2w_2=C_3w_3

where,

C_1 = concentration of ist progesterone gel = 8%w/w

w_1 = weight of ist progesterone gel  = x g

C_2 = concentration of another progesterone gel  = 4% w/w

w_2 = weight of another progesterone gel = 1.45 g

C_3 = concentration of resulting progesterone gel  = 5.5%w/w

w_3 = weight of resulting progesterone gel  = (x+1.45) g

8\times x+4\times 1.45=5.5\times (x+1.45)

x=0.87

Thus 0.87 g of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel.

4 0
4 years ago
How many molecules of hydrogen chloride gas could theoretically be produced at STP by reacting 34.7 liters of hydrogen gas at ST
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Answer:

69.4

Explanation:

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It is difficult to press the football in water why?​
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Answer:

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Explanation:

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Carbon has 6 protons and 8 neutrons.
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