Complete question:
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.
Answer:
The magnitude of q for the process 568 J.
Explanation:
Given;
change in internal energy of the gas, ΔU = 475 J
work done by the gas, w = 93 J
heat added to the system, = q
During gas expansion process, heat is added to the gas.
Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.
ΔU = q - w
q = ΔU + w
q = 475 J + 93 J
q = 568 J
Therefore, the magnitude of q for the process 568 J.
Answer:
4.36 g of Carbon
Solution:
Step 1: Calculate the %age of Carbon in given Solid as;
Mass of Carbon = 35.8 g
Mass of Hydrogen = 3.72
Total Mass = 35.8 g + 3.72 = 39.52 g
%age of Carbon = (35.8 g ÷ 39.52 g) × 100
%age of carbon = 90.58 %
Step 2: Calculate grams of Carbon in 4.82 g of given solid as;
Mass of Carbon = 4.82 g × (90.58 ÷ 100)
Mass of Carbon = 4.36 g
Answer:
my answer is b oti d I am not sure
Answer:
its already in scientific notation form however its ordinary or real form is -0.005682
Explanation:
scientific notation
when a number is expressed with some power of 10 multiplied by a number between 1 to 10 is called scientific notation
The IUPAC rules are
a) Find out the longest chain of carbon in the given organic compound
b) We will name the longest chain.
c) We will identify the main functional group and will assign a suffix to the compound.
d) We will number the carbons in the longest chain selected so that the attached groups attain lowest numeral as substituent
e) We will name the side groups or chains.
