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wariber [46]
3 years ago
6

Light with a single wavelength falls on two slits separated by 0.510 mm. In the resulting interference pattern on a screen 2.24

m away, adjacent bright fringes are separated by 2.88 mm.What is the wavelength of the light that falls on the slits
Physics
1 answer:
scZoUnD [109]3 years ago
7 0

Answer: 655.7 nm

Explanation:

Given

The slits are separated by d=0.510\ mm

Distance between slits and screen is D=2.24\ m

Adjacent bright fringes are \beta =2.88\ mm apart

Also, the distance between bright fringes is given by  

\Rightarrow \beta =\dfrac{\lambda D}{d}\quad [\lambda=\text{Wavelength of light}]\\\\\text{Insert the values}\\\\\Rightarrow 2.88\times 10^{-3}=\dfrac{\lambda \cdot 2.24}{0.510\times 10^{-3}}\\\\\Rightarrow \lambda =\dfrac{2.88\times 10^{-3}\times 0.510\times 10^{-3}}{2.24}\\\\\Rightarrow \lambda =0.6557\times 10^{-6}\ m\\\Rightarrow \lambda =655.7\ nm

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