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3 years ago

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1. A meteorologist describes a tropical storm as traveling northwest at 50 mi/h. Which attribute of the storm's motion has the m

eteorologist described? A. force C. velocity B. acceleration D. displacement

1 answer:

kirza4 [7]3 years ago

6 0

The answer is B. Acceleration.

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The hot glowing surfaces of stars emit energy in the form of electromagnetic radiation. It is a good approximation to assume tha

belka [17]

Given that,

Energy $H=2.7\times10^{31}\ W$

Surface temperature = 11000 K

Emissivity e =1

(a). We need to calculate the radius of the star

Using formula of energy

$H=Ae\sigma T^4$

$A=\dfrac{H}{e\sigma T^4}$

$4\pi R^2=\dfrac{H}{e\sigma T^4}$

$R^2=\dfrac{H}{e\sigma T^4\times4\pi}$

Put the value into the formula

$R=\sqrt{\dfrac{2.7\times10^{31}}{1\times5.67\times10^{-8}\times(11000)^4\times 4\pi}}$

$R=5.0\times10^{10}\ m$

(b). Given that,

Radiates energy $H=2.1\times10^{23}\ W$

Temperature T = 10000 K

We need to calculate the radius of the star

Using formula of radius

$R^2=\dfrac{H}{e\sigma T^4\times4\pi}$

Put the value into the formula

$R=\sqrt{\dfrac{2.1\times10^{23}}{1\times5.67\times10^{-8}\times(10000)^4\times4\pi}}$

$R=5.42\times10^{6}\ m$

Hence, (a). The radius of the star is $5.0\times10^{10}\ m$

(b). The radius of the star is $5.42\times10^{6}\ m$

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3 years ago

A waiter is carrying a tray above his head and walking at a constant velocity. If he applies a force of 5.0 newtons on the tray

k0ka [10]

W = f × x = 5 × 10 = 50

4 0

3 years ago

Read 2 more answers

The speed of sound in humid air than in dry air. Why

Elden [556K]

Answer:

When moisture is removed from air, its density increases. The speed of sound in a humid air is inversely proportional to the square root of its density. Therefore, the speed of sound in moist air is humidity increases, the velocity of sound increase and vice-versa.

Hope it helps :)

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3 years ago

the earth had a mass of 6,000,000,000,000,000,000,000,000 kg. and a radius of 6,371,000 m, what will be the gravitational force

Semmy [17]

Answer:

Mass of Earth (M1) = 6×10^24 kg

Mass of Puppy (M2) = 3.6 kg

Radius (R) = 6371000 m

Universal Gravitational Constant (G) = 6.67 × 10^11

Now,

Gravitational Force = G×M1×M2 / R^2

GF = 6.67 × 10^11 × 6 × 10^24 × 3.6 / (6371000)^2

GF = 144.072 × 10^35 / 40,589,641,000,000

GF = 3549.477 × 10^20

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2 years ago

A 7.5 kg cannon ball leaves a canon with a speed of 185 m/s. Find the average net force applied to the ball if the cannon muzzle

schepotkina [342]

We would like to know the average net force. Therefore, we can calculate the acceleration using:

x = 0.5*a*t^2

v = a*t

where x=3.6m and v=185 m/s.

Therefore,

t=v/a and hence x = 0.5*a*(v/a)^2 = 0.5 * (v^2)/a

so a= (0.5*v^2)/x

Since we know the values for v and x, as written above, we can calculate a by plugging the numbers in.

The average net force will then be:

F = m*a,

where m=7.5kg.

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3 years ago