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Semenov [28]
3 years ago
13

A 3.6-volt battery is used to operate a cell phone

Physics
2 answers:
Andrei [34K]3 years ago
4 0
The equation with the values for this one is P = VI, and we know some of the values, so substituting them in:

0.064 = 3.6 x I
I=0.064/3.6
=0.0177 = 0.018A
Marina CMI [18]3 years ago
3 0

Explanation :

It is given that,

Potential energy, V=3.6\ V

Power dissipated,  P=0.064\ Watt

We know that the power dissipated is given by :

P=VI

I is the current passing through the phone.

I=\dfrac{P}{V}

I=\dfrac{0.064\ W}{3.6\ V}

I=0.017\ A

or

I = 0.018 A

Hence, the current that passes through the phone is (1) 0.018 A.

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I understand that the question you are looking for is "Consider two copper wires of equal cross-sectional area. One wire has 3 times the length of the other. How do the resistances of these two wires compare?

A) Both wires have the same resistance.

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D) The longer wire has 9 times times the resistance of the shorter wire.

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