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masha68 [24]
3 years ago
5

What is chemical change ?​

Chemistry
2 answers:
nikitadnepr [17]3 years ago
8 0

\huge{ \color{violet}{ \boxed{ \color{hotpink}{Answer}}}}

<h3>➣ Chemical Change</h3>
  • It occurs when new materials are formed by a change in the way the atoms are bonded together.

  • Heat, light or electrical energy is often emmitted or absorbed.

\:

\large\tt\:⚘ \: MishiChaeYoon \: ⚘

Ksju [112]3 years ago
3 0
Change in chemical bonds that alters what a reaction would be

Pls give me a brainliest thx
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4 0
3 years ago
Calculate the Kelvin temperature to which 10.0 L of a gas at 27 °C would have to be heated to change the volume to 12.0 L. Units
KatRina [158]

Hello!

For this problem, we will be applying <em>Charles' Law</em>:

V1/T1 = V2/T2

Now that we have the formula, let's convert the temperature to Kelvin.

27 + 273 = 300K

Let's plug everything in now!

10/300 = 12.0/x

Simplified:

1/30 = 12.0/x

Cross-multiply:

1x = 30*12.0

<u>x = 360</u>

<em>Check!</em>

10/300 = 12/360

300*12 = 360*10

3600 = 3600

Therefore, you would have to heat the gas at a temperature of 360K in order to raise the volume to 12.0L.

 

4 0
3 years ago
For the reaction 2H2+O2 2H2O how many liters of water can be made from 5.00 L of oxygen gas and an excess of Hydrogen at STP
Veseljchak [2.6K]
5L O2 x 1 mol O2/ 22.4L O2 x 2 mol H20/ 1 mol O2 x 22.4L H20/ 1 mol H20 = 10 L H2O
For future reference though, since its at STP that means that the coefficient are in proportion. Since oxygen has a coefficient of 1 and water has a coefficient of 2 for every 1 liter of oxygen there is 2 liters of water. Hence you started with 5 liters and ended with 10
8 0
3 years ago
If 1.0 M HIM HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C∘C, what is the equili
sattari [20]

The given question is incomplete. The complete question is

If 1.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C∘C, what is the equilibrium concentration of H2 (g). Given the equilibrium constant is 62.

Answer: The equilibrium concentration of H_2 is 0.498 M

Explanation:

Initial concentration of HI = 1.0 M

The given balanced equilibrium reaction is,

                         2HI(g)\rightarrow H_2(g)+I_2(g)

initial                  (1.0) M                  0              0

At eqm               (1.0-2x) M               (x) M      (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[H_2]\times [I_2]}{[HI]^2}

Now put all the given values in this expression, we get :

62=\frac{(x)^2}{1.0-2x}

By solving we get :

x=0.498M

Thus the equilibrium concentration of H_2 is 0.498 M

6 0
3 years ago
HELP POINTS!!!!!<br><br> What is stoichiometry?
Vlad [161]
Stoichiometry measures these quantitative relationships, and is used to determine the amount of products/reactants that are produced/needed in a given reaction.
8 0
3 years ago
Read 2 more answers
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