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ollegr [7]
3 years ago
8

Lithium was one of the metals studied by the American physicist Robert Millikan in his research on the photoelectric effect. Whe

n illuminated with blue light of frequency 6.64 x 10" Hz, the photoelectrons ejected from a lithium surface have a maximum kinetic energy of 0.332 eV. What is the threshold frequency for lithium? For this problem, let the value of Planck's constant, h, be 6.63 x 10J's
Physics
1 answer:
faltersainse [42]3 years ago
4 0

Answer:

 f = 7.9487 10¹³ Hz

Explanation:

The photoelectric effect was correctly explained by Einstein assuming that the radiation is composed of photons, which behave like particles.

           hf = K + Ф

It indicates the frequency and the kinetic energy, let's look for the work function

          Ф = hf - K

let's reduce the magnitudes to the SI system

          K = 0.332 eV (1.6 10⁻¹⁹ J / 1 eV) = 0.5312 10⁻⁻¹⁹ J

let's calculate

          Ф = 6.63 10⁻⁻³⁴  6.64 10¹¹ - 0.5312 10⁻¹⁹

          Ф = 4.40 10⁻²² - 0.5312 10⁻¹⁹

          Ф = 5.27 10⁻²⁰ J

for the minimum frequency that produces photoelectrons, the kinetic energy is zero

           hf = Ф  

           f = Ф / h

           f = 5.27 10⁻²⁰ / 6.63 10⁻³⁴

           f = 7.9487 10¹³ Hz

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A river flows due east at 1.60 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant v
Citrus2011 [14]

Answer:

part (a) v\ =\ 10.42\ at\ 81.17^o towards north east direction.

part (b) s = 46.60 m

Explanation:

Given,

  • velocity of the river due to east = v_r\ =\ 1.60\ m/s.
  • velocity of the boat due to the north = v_b\ =\ 10.3\ m/s.

part (a)

River is flowing due to east and the boat is moving in the north, therefore both the velocities are perpendicular to each other and,

Hence the resultant velocity i,e, the velocity of the boat relative to the shore is in the North east direction. velocities are the vector quantities, Hence the resultant velocity is the vector addition of these two velocities and the angle between both the velocities are 90^o

Let 'v' be the velocity of the boat relative to the shore.

\therefore v\ =\ \sqrt{v_r^2\ +\ v_b^2}\\\Rightarrow v\ =\ \sqrt{1.60^2\ +\ 10.3^2}\\\Rightarrow v\ =\ 10.42\ m/s.

Let \theta be the angle of the velocity of the boat relative to the shore with the horizontal axis.

Direction of the velocity of the boat relative to the shore.\therefore Tan\theta\ =\ \dfrac{v_b}{v_r}\\\Rightarrow Tan\theta\ =\ \dfrac{10.3}{1.60}\\\Rightarrow \theta\ =\ Tan^{-1}\left (\dfrac{10.3}{1.60}\ \right )\\\Rightarrow \theta\ =\ 81.17^o

part (b)

  • Width of the shore = w = 300m

total distance traveled in the north direction by the boat is equal to the product of the velocity of the boat in north direction and total time taken

Let 't' be the total time taken by the boat to cross the width of the river.\therefore w\ =\ v_bt\\\Rightarrow t\ =\ \dfrac{w}{v_b}\\\Rightarrow t\ =\ \dfrac{300}{10.3}\\\Rightarrow t\ =\ 29.12 s

Therefore the total distance traveled in the direction of downstream by the boat is equal to the product of the total time taken and the velocity of the river\therefore s\ =\ u_rt\\\Rightarrow s\ =\ 1.60\times 29.12\\\Rightarrow s\ =\ 46.60\ m

7 0
3 years ago
A 0.50 kg object is attached to a spring with force constant 157 N/m so that the object is allowed to move on a horizontal frict
Genrish500 [490]

Explanation:

We have,

Mass of an object is 0.5 kg

Force constant of the spring is 157 N/m

The object is released from rest when the spring is compressed 0.19 m.

(A) The force acting on the object is given by :

F = kx

F=157\times 0.19\\\\F=29.83\ N

(B) The force is simply given by :

F = ma

a is acceleration at that instant

a=\dfrac{F}{m}\\\\a=\dfrac{29.83}{0.5}\\\\a=59.66\ m/s^2

6 0
3 years ago
If an object has a mass of 20 kg, what is the force of gravity acting on it on earth?
stealth61 [152]

That force is what most people would call the object's "weight".

Wherever the object is, its weight is

                            (mass) x (acceleration due to local gravity) .

On Earth, the acceleration due to gravity is   9.8 m/s² . (rounded)

The object's weight is      (20 kg) x (9.8 m/s²)  =  196 newtons .

                                                                   (about 44.1 pounds)

7 0
3 years ago
Read 2 more answers
Tarzan (mT=85.0 kg) is perched on a cliff 16.0 m above Jane. Jane is in the foreground is looking forwards. In the background, T
poizon [28]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Part A

The velocity of Tarzan is   v_T = 17.7 \ m/s

Part B

The percentage loss of kinetic energy is  %-loss  = 61.4%

Part C

The speed would be exactly the same

Explanation:

From the question we are told that

       The mass of Tarzan is m = 85.5 \ kg

          The height of the cliff is h = 16.0 \ m

           

From the law of conservation of energy

             PE = KE

Where PE is the potential energy of Tarzan at the top of the cliff which is mathematically represented as

            PE = mgh

        KE is the kinetic energy of Tarzan as he swings toward jane and is mathematically represented as

           KE = \frac{1}{2} mv^2_T

  So

            mgh = \frac{1}{2}m v_T^2

=>        gh = \frac{1}{2} v_T^2

Substituting values

             9.8 * 16 = \frac{1}{2} v_T^2

=>           v_T = \sqrt{\frac{9.8 * 16}{0.5} }

             v_T = 17.7 \ m/s

From the question we are told that the actual velocity of Tarzan is

            v = 11 m/s

The kinetic energy at the the velocity is mathematically represented as

         KE_A = \frac{1}{2} m v^2

Substituting values

          KE_A = \frac{1}{2} (85) *   11^2

          KE_A =  5142.5 J          

The kinetic energy at v_T is  

       KE =  \frac{1}{2}  * 85 * 17.7^2

=>     KE =  13314.83\ J

Now the percentage loss of kinetic energy is mathematically evaluated as

       %-loss  = \frac{KE -  KE_A}{KE}  * 100

substituting values

             %-loss  = \frac{13314.83 -  5142.5}{13314.83}  * 100

                %-loss  = 61.4%

The mass of Tarzan does not affect the speed because looking at this equation

                gh = \frac{1}{2} v_T^2

We see that the velocity of Tarzan is not dependent on the mass of Tarzan

4 0
3 years ago
Two persons A and B do same amount of work. The person A does that work in t1sec and the person b in t2sec. Find the ratio of po
MissTica

The ratio between power of A and power of B is 2

Explanation:

In physics, power is defined as the ratio between the work done and the time taken to do the work:

P=\frac{W}{t}

where

P is the work done

t is the time taken

In this problem, we have:

Person A and person B do the same amount of work --> let's call this work W

Person A does this work in a time of t_A = 1 s, so the power delivered by A is

P_A = \frac{W}{1}=W

Person B does this work in a time of t_B = 2 s, so the power delivered by B is

P_B = \frac{W}{2}

So, the ratio of the powers delivered by the two persons is

\frac{P_A}{P_B}=\frac{W}{W/2}=2

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

4 0
3 years ago
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