In a closed system, a cart with a mass of 1.5 kg is rolling to the right at 1.4 m/s, while another cart of mass 1.0 kg is rollin
2 answers:
Answer: The correct option is (c.).
Explanation:
Mass of the cart A= 1.5 kg
Velocity of Cart A = 1.4 m/s towards right
Mass of the cart B = 1.0 kg
Velocity of Cart B = 1.4 m/s towards left
Momentum (P)= Mass × Velocity
(Negative sign means velocity of the cart is in opposite direction of that of the cart A)
Total Momentum =
Hence, the correct option is (c.).
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Answer:
For vector u, x component = 10.558 and y component =12.808
unit vector = 0.636 i+ 0.7716 j
For vector v, x component = 23.6316 and y component = -6.464
unit vector = 0.9645 i-0.2638 j
Explanation:
Let the vector u has magnitude 16.6
u makes an angle of 50.5° from x axis
So
Vertical component
So vector u will be u = 10.558 i+12.808 j
Unit vector
Now in second case let vector v has a magnitude of 24.5
Making an angle with -15.3° from x axis
So horizontal component
Vertical component
So vector v will be 23.6316 i - 6.464 j
Unit vector of v
the enclosed may help. earth rotes and you and i are fixed to it. air flows it's own path ...
Answer:
the question is incomplete, the complete question is
"A circular coil of radius r = 5 cm and resistance R = 0.2 ? is placed in a uniform magnetic field perpendicular to the plane of the coil. The magnitude of the field changes with time according to B = 0.5 e^-t T. What is the magnitude of the current induced in the coil at the time t = 2 s?"
2.6mA
Explanation:
we need to determine the emf induced in the coil and y applying ohm's law we determine the current induced.
using the formula be low,
where B is the magnitude of the field and A is the area of the circular coil.
First, let determine the area using where r is the radius of 5cm or 0.05m
since we no that the angle is at
we determine the magnitude of the magnetic filed
the Magnitude of the voltage is 0.000532V
Next we determine the current using ohm's law