Answer:
1.31M
Explanation:
Based on the reaction, 1 mole of Zn produce 1 mole of ZnCl₂. As the reaction occurs completely, the moles of Zn added = Moles of ZnCl₂ produced. To find molarity we need the moles of ZnCl₂ and the volume of the solution in liters:
<em>Moles Zn = Moles ZnCl₂ -Molar mass Zn: 65.38g/mol-:</em>
15g * (1mol / 65.38g) = 0.23 moles of ZnCl₂
<em>Volume in Liters:</em>
175mL * (1L / 1000mL) = 0.175L
The molarity is:
0.23moles / 0.175L
<h3>1.31M</h3>
Cd2+ + 2Hg Cd + Hg22+. Both Cd2+ + 2e Cd(s) -0.40 and Hg22+ + 2e 2Hg(l) 0.79
A chemical reaction known as an oxidation-reduction (redox) reaction includes the exchange of electrons between two substances.
Any chemical reaction in which the oxidation number of a molecule, atom, or ion changes by acquiring or losing an electron is referred to as an oxidation-reduction reaction. Decomposition Reaction is one of the several redox reactions.
This is the redox reaction's overall cell potential. Cd2+ + 2Hg Cd + Hg22+. Both Cd2+ + 2e Cd(s) -0.40 and Hg22+ + 2e 2Hg(l) 0.79
Reduction describes the increase in electrons. Oxidation and reduction always occur jointly because any loss of electrons by one substance must be followed by a gain of electrons by another.
Therefore, oxidation-reduction processes or simply redox reactions are other names for electron-transfer events.
Learn more about redox reactions here brainly.com/question/8727728.
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Answer:
option b. B3+
Explanation:
Boron takes the 5th position on the periodic table, therefore it has 5 electrons....2 on the inside and 3 on the outside. when it lost it 3 external electrons, it become positively charged with the amount of electron it loses.
Answer:
C) 35%
Explanation:
Thymine pairs with adenine. If thymine is 15% then so would adenine be 15%. That leaves the reaminder to be 70%. Cytosine pairs with guanine, thereby, they would each be 35%.
Answer:
5446.8 J
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 50 g
Initial temperature (T₁) = 70 °C
Final temperature (T₂) = 192.4 °C
Specific heat capacity (C) = 0.89 J/gºC
Heat (Q) required =?
Next, we shall determine the change in the temperature. This can be obtained as follow:
Initial temperature (T₁) = 70 °C
Final temperature (T₂) = 192.4 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 192.4 – 70
ΔT = 122.4 °C
Finally, we shall determine the heat required to heat up the block of aluminum as follow:
Mass (M) = 50 g
Specific heat capacity (C) = 0.89 J/gºC
Change in temperature (ΔT) = 122.4 °C
Heat (Q) required =?
Q = MCΔT
Q = 50 × 0.89 × 122.4
Q = 5446.8 J
Thus, the heat required to heat up the block of aluminum is 5446.8 J
