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sergeinik [125]
3 years ago
9

In an isothermal process, 1.59 moles of an ideal gas is compressed to one-fifth of its initial volume at 285 K. What quantity of

heat is added to, or removed from, the system during this process
Chemistry
1 answer:
Nataly_w [17]3 years ago
5 0

Answer:

−6063.54 J  of heat is removed from the system during this process.

Explanation:

Given that :

in an isothermal process

number of moles of an ideal gas =  1.59 moles

which is compressed to one- fifth of its initial volume

Let say the initial volume = x

the final volume will be = x/5

Temperature = 285 K

The objective is to determine what quantity of heat is added to, or removed from, the system during this process.

In an isothermal process;

q = w

where ;

w = nRT In (V₂/V₁)

w = 1.59 × 8.314 × 285 × In (x/5 /x)

w = 1.59 × 8.314 × 285 × In (1/5)

w = −6063.54 J

Thus;  −6063.54 J  of heat is removed from the system during this process.

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Answer:

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Explanation:

10.00 mL of solution A was diluted to 50.00 mL and yields 50.00 mL of solution B

According to laws of dilution-      C_{A}V_{A}=C_{B}V_{B}

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Hence, C_{A}=\frac{C_{B}V_{B}}{V_{A}}=\frac{(0.1045M\times 50.00mL)}{10.00mL}=0.5225M

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