Answer:
0.444 mol/L
Explanation:
First step is to find the number of moles of oxalic acid.
n(oxalic acid) = 
Now use the molar ratio to find how many moles of NaOH would be required to neutralize
of oxalic acid.
n(oxalic acid): n(potassium hydroxide)
1 : 2 (we get this from the balanced equation)
: x
x = 0.0111 mol
Now to calculate what concentration of KOH that would be in 25 mL of water:

Answer:
c
Explanation:
because nothing is changing, so what are you gonna track with the line graph
Landsat - (USA)
Spot - (France)
Radarsat (Canada)
Answer:
The net ionic equation for the given reaction :

Explanation:
...[1]
..[2]
...[3]

Replacing
, NaI and
in [1] by usig [2] [3] and [4]

Removing the common ions present ion both the sides, we get the net ionic equation for the given reaction [1]:
