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solmaris [256]
3 years ago
6

Please help. Thank you guys for all your help and support. <3

Chemistry
2 answers:
miv72 [106K]3 years ago
7 0
It would be “To obey the law of conservation of mass”
dalvyx [7]3 years ago
6 0
Option D, to obey the conservation of mass.

The conservation of mass essentially states that all the atoms in a chemical reaction will still be there once the chemical reaction is complete.
Because of this, you have to balance chemical equations in order to ensure that there isn't a surplus or deficit of atoms on either side.

-T.B.
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What is the chemical name of the covalent compound P4O9?
Lunna [17]

P4O9 is an oxide of phosphorous

so it will named accordingly

There are four phosphorous atoms and nine oxygen atoms

four will be represented as "tetra"

Nine will represented as "non"

so the name of the compound will be

tetraphosphorous nonoxide


3 0
3 years ago
Calculate and record the expected mass of benzoic acid required to react with 20.00 ml of a 0.100 m sodium hydroxide solution. r
Marina CMI [18]
Benzoic acid reacts with sodium hydroxide based on the equation shown in the attached picture.

It is clear that the ration between the benzoic acid and the sodium hydroxide is 1:1 in this reaction.

So, to answer this question, we will calculate the number of moles of sodium hydroxide used, equate it to the number of moles of benzoic acid and then calculate the mass of the calculated number of moles.

molarity = number of moles of solute / liter of solvent
0.1 = number of moles of sodium hydroxide / 0.02 liters
number of moles of sodium hydroxide = 0.002 moles

Therefore, number of moles of benzoic acid is also 0.002 moles
molar mass of benzoic acid = <span>122.12 grams

Therefore, the required mass of benzoic acid = 0.002 x </span><span>122.12
                                                                         = 0.2444 moles</span>

5 0
3 years ago
Consider the reaction between hydrazine and hydrogen to produce ammonia, N2H4(g)+H2(g)→2NH3(g). Use enthalpies of formation and
sammy [17]

Answer:

The answer is explained below:

Explanation:

Given the chemical equation:

                   N2H4(g)+H2(g)→2NH3(g)

The standard enthalpy of formation is given by the following formula:

            ΔH^0 rxn = ∑ B reactants - ∑ product

       -187.78 kJ/mol = [( 1x B N-N) + (1 x B N-H ) + (1 x b H-H)] - [ 6 x B N-H]

       -187.78 kJ/mol = [( 1x B N-N)  +(4 x 391 kJ/mol) + (1 x 436  kJ/mol)] - [ 6x 391  kJ/mol ]

        -187.78 kJ/mol =  B N-N  + (1564 + 436 - 2346) kJ/mol

                                       B   = 158.22 kJ/mol

So, in this case the enthalpy of N-N bond is 158 kJ/mol

6 0
3 years ago
A (what) forms when the sperm first fertilizes an egg
Arlecino [84]
Fertilization occurs when the nucleus of both a sperm and egg fuse to form a diploid cell known as zygote the successful fusion of gametes forms a new organization
7 0
3 years ago
4). One mole of monoclinic sulfur at 25C was placed in a constant-pressure calorimeter whose heat capacity (C) was 1620 J/K. T
andre [41]

<u>Answer:</u> The enthalpy change of the reaction is -243 J/mol

<u>Explanation:</u>

The heat released by the reaction is absorbed by the calorimeter and the solution.

The chemical equation used to calculate the heat released follows:

q=c\times \Delta T

where,

c = heat capacity of calorimeter = 1620 J/K

\Delta T = change in temperature = 0.150^oC=0.150K   (Change remains same)

Putting values in above equation, we get:

q=1620J/K\times 0.15K=243J

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

For the given chemical reaction:

S\text{ (monoclinic)}\rightarrow S\text{ (orthorhombic)}

We are given:

Moles of monoclinic sulfur = 1 mole

  • To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,  

q = amount of heat released = -243 J

n = number of moles = 1 mole

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{-243J}{1mol}=-243J/mol

Hence, the enthalpy change of the reaction is -243 J/mol

8 0
3 years ago
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