<u>Answer:</u> The amount of p-toluidine hydrochloride contained is 2.4 moles.
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:

Molarity of p-toluidine hydrochloride solution = 0.167 M
Volume of solution = 70. mL
Putting values in equation 1, we get:

Hence, the amount of p-toluidine hydrochloride contained is 2.4 moles.
Answer:
(D) greater than the energy stored in the bonds of the products.
Explanation:
Exothermic reaction refer to those reactions in which energy is released to the surrounding, unlike endothermic reactions where energy is absorbed from the surroundings.
In exothermic reactions, the change in energy; ΔH less than zero. That is, they are negative.
ΔH = H (products) - H (reactants)
For ΔH to have a negative value, it means the energy of reactant must be greater than the energy of products.
This means the correct option is;
(D) greater than the energy stored in the bonds of the products.
Answer:
Oxidation states are used in chemistry solutions. It is a bond in which electron transfers easily from one nucleus to another nucleus.
Explanation:
- Oxidation-reduction reactions have some rules.
- The oxidation state is 0 at an uncombined bond.
- The bond of oxidation reduction is +1 in alkeli metal.
- The bond in two metal is +2
- The oxidation reduction state at helogens is -1. It does not happened always.
- The oxygen bond in oxidation and reduction is -2.
- The sum of the oxidation state is equal to the compound charges.
- In this process the changes occur for any elements. Redox could be occur. Its oxidized and reduction reaction can be seen in this process.
Answer:
Nanomachines will work with atoms, not nuclei. The smallest unit of a chemical element, about a third of a nanometer in diameter. Atoms make up molecules and solid objects.
Explanation:
Answer:
Explanation:
The movement of the electrons is illustrated in the picture attached to this answer. It is a four-step reaction mechanism.
First STEP: The first step involves the transfer of an electron from sodium to form a radical anion.
Second STEP: This radical anion then removes a proton/hydrogen from ammonia in a bid to neutralize itself (hence the hydrogen becomes bonded to the anion).
Third STEP: The sodium (from NaNH₂ formed) transfers an electron again to produce a vinyl carbanion.
Fourth STEP: The carbanion then removes a proton/hydrogen from ammonia (like in the second step) to form a neutral trans-alkene.
NOTE: The circled numbers denote each step while the mechanism on the left represents the use of any alkyl group (R and R') while the mechanism on the right assumes both alkyl groups are methyl. Hence, 2-butyne started the reaction and the final product was trans-2-butene.