Answer:
70 g
Explanation:
ice at zero degree will melt and cool down water from 20 degree to 5 degree
heat gained by ice in melting
= mass x heat of fusion
= m x 333.7 x 10³ J
Heat gained by water at zero to water at 5 degree
= mass x specific heat x rise in temperature
= m x 4.18 x 10³ x 5
Total heat gained
= m x 333.7 x 10³ +m x 4.18 x 10³ x 5
= 354.6 x 10³ m J
mass of water = .4 x 1
= .4 kg
heat lost by hot water at 20 degree to 5 degree
= .4 x 4.18 x 10³ x ( 20-5 )
=25.08 X 10³ J
Heat lost = heat gained
354.6 x 10³ m = 25.08 X 10³
m = 25.08 / 354.6
= .070 kg
70 g
b )
Let the water required be m kg
heat gained by water
= m x 4.18 x 10³ x 15
m x 4.18 x 10³ x 15 = 25.08 X 10³
m = 25.08 / (4.18 x 15)
= .4 kg
= 400 gm
=
Jeremy accidently dropped his toy stuffed animal from the balcony of his apartment on the fourth floor. The toy hit the ground at a velocity of 16.0 meters/second. At impact, it took 2.0 seconds for the toy's velocity to reach 0 meters/second. If the toy has a mass of 0.25 kilograms, what's the force of the impac
When a warm air mass and a cold air mass collide, you get a front. Remember how low-pressure warm air rises and cold high-pressure air moves into its place? The same reaction happens here, except the two forces slam into each other. The cold air forms a wedge underneath the warm air, allowing it to basically ride up into the troposphere on its back and generate rain clouds. There are four main kinds of fronts, classified by airflow momentum. In a warm front, a warm air mass moves into a cold air mass. In a cold front, the opposite occurs. In a stationary front, neither air mass advances. Think of it as two fronts bumping into each other by accident. In an occluded front, a cold front overtakes a moving warm front, like an army swarming over a fleeing enemy.
The work that you do on the lever will be the same as the work done by the lever on the rock. This aligns with the Law of the Conservation of Energy which states that energy can not be created nor destroyed. Since work can be calculated as force applied over a distance, you will apply a smaller force but your distance will be longer. The lever will apply a greater force over a shorter distance in proportion to yours. Therefore, the same amount of work is done on both sides of the lever.
Hi there!
We can begin by calculating the distance remaining after the reaction time.
Δd = vt
Calculate the distance traveled within this time:
Δd = (16)(.79) = 12.64 m
Subtract from the total distance:
150 - 12.64 = 137.66 m remaining
We can use the following equation to solve for the acceleration necessary:
vf² = vi² + 2ad, where vf = 0 since the train will have slowed down to rest.
Rearrange in terms of "a":
0 = vi² + 2ad
(-vi²) = 2ad
(-vi²)/2d = a
Plug in the given values:
(-(16²))/2(137.66) = a
-256/275.32 = -.9298 m/s²